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Does e^ln = 1?

Does e^ln = 1?
Any help would be appreciated!!
Original post by metaljoe
Does e^ln = 1?
Any help would be appreciated!!


e to the ln of what? It's true that eln∣x∣=∣x∣e^{ln|x|}=|x| but that's only equal to 1 for x=1x=1.
Original post by metaljoe
Does e^ln = 1?
Any help would be appreciated!!


e^ln is an invalid expression - ln is not taking in any arguments.
Yes.
e^Ln(1) = 1
e^ln doesn't mean anything, you can't have a ln without a value of some kind
ln(1)=0,e0=1ln(1) = 0, e^0 = 1 so
Unparseable latex formula:

e^l^n^(^1^) = 1

Reply 6
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metaljoe
OP
7
The question I was answering was:

Solve the following equations, giving your answers in exact form:

ln | 3x - 1 | = 4

I took both sides to the power of e leaving:

e^ln|3x-1| = e^4

So I was wondering if e^ln = 1 times what ever is the power of e^ln?
Original post by metaljoe
The question I was answering was:

Solve the following equations, giving your answers in exact form:

ln | 3x - 1 | = 4

I took both sides to the power of e leaving:

e^ln|3x-1| = e^4

So I was wondering if e^ln = 1 times what ever is the power of e^ln?


You have to have the natural log of something. ex e^x and ln(x) ln(x) are inverses and f−1(fg(x))=g(x) f^{-1}(fg(x)) = g(x)

so if f(x) = e^x, then f−1(x)=ln(x) f^{-1}(x) =ln(x)

so, e^ln|3x-1| = |3x-1|
Reply 8
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metaljoe
OP
7
Original post by NotNotBatman
You have to have the natural log of something. ex e^x and ln(x) ln(x) are inverses and f−1(fg(x))=g(x) f^{-1}(fg(x)) = g(x)

so if f(x) = e^x, then f−1(x)=ln(x) f^{-1}(x) =ln(x)

so, e^ln|3x-1| = |3x-1|


Cheers buddy!!!
Reply 9
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metaljoe
OP
7
Thanks everyone all sorted now!!!!

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