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First ionisation energy equations.. help?!

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TSR's new app is coming! Sign up here to try it first >> 17-10-2016
    • Thread Starter

    (Original post by GabbytheGreek_48)
    Actually energy levels go 1s^2 2s^2 2p^6 3s^2 3p^1 (for aluminium which had 13 electrons)

    So for each respective ionisation just take off an electron if there are no electrons left in that she'll then you don't write it in the configuration

    Posted from TSR Mobile
    (Original post by CheeseIsVeg)
    You are along the right lines.
    So Aluminium has 13 electrons
    These lie in the 1s2 2s2 2p6 3s2 3p1 sub shells
    the question ends in 3s1
    I have bolded where 3s1 is in aluminium's full electronic configuration
    How many ionisations is this?Well 3p1 = 1, to get to 3s1 we then knock off another electron, therefore it would be 2nd ionisation (2 electrons lost )
    thanks for all the help guys, hopefully I'll understand it more when we cover orbitals in class?? aha

    (Original post by LDS16)
    thanks for all the help guys, hopefully I'll understand it more when we cover orbitals in class?? aha
    best of luck, you know where to find me if you need

    You guys have done ionisation energy without doing sub shells o.o

    Posted from TSR Mobile
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