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A2 Maths C3 questions

Change one value in the expression so that there is a linear divisor in the remainder when simplified
x^3-2x^2+6x-8/x^2+3x-4
Original post by YUANHANGCHEN
Change one value in the expression so that there is a linear divisor in the remainder when simplified
x^3-2x^2+6x-8/x^2+3x-4


so im assuming you done the long division and got as far as;

x32x2+6x8x2+3x4=x5+25x28x2+3x4 \displaystyle \frac{x^3 -2x^2 + 6x - 8}{x^2 +3x -4} \: = \: x- 5 + \frac{25x - 28}{x^2 + 3x -4}

well if I was to tell you that for some value "a" ; x32x2+6xax2+3x4=x5+25x20ax2+3x4 \displaystyle \frac{x^3 -2x^2 + 6x - a}{x^2 +3x -4} \: = \: x- 5 + \frac{25x - 20 - a}{x^2 + 3x -4} , does that help any?

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