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# Core 3 - solving mod function - Help

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1. Hello

I've solved a mod equation (in image) and the next question is asking me to solve the same equation, involving logs:

(I'm stuck on the question I put a box around)

I'm unsure how to use my previous answer (also in image) to answer this "hence" question

Posted from TSR Mobile
2. (Original post by Yusufff)
Hello

I've solved a mod equation (in image) and the next question is asking me to solve the same equation, involving logs:

(I'm stuck on the question I put a box around)

I'm unsure how to use my previous answer (also in image) to answer this "hence" question

Posted from TSR Mobile
There is one key difference between - a substitution.. (you could swap out the x's for ys in your first answer if it helps.. for the second part, that is).
3. Ok so I'm up to here, would I take the natural log of everything to bring the power of x down?

(Original post by SeanFM)
There is one key difference between - a substitution.. (you could swap out the x's for ys in your first answer if it helps.. for the second part, that is).

Posted from TSR Mobile
4. (Original post by Yusufff)
Ok so I'm up to here, would I take the natural log of everything to bring the power of x down?

Posted from TSR Mobile
Correctamundo so what does that give you?
5. (Original post by SeanFM)
Correctamundo so what does that give you?
I got 1/3 < x < 4/3 - which seems correct? If so thanks for your help
7. (Original post by Yusufff)
I got 1/3 < x < 4/3 - which seems correct? If so thanks for your help
Yes you'll see that fits into 2 < 8^x < 16 so it must be correct

(Original post by mariam687)

I'm sure you'd ace it if you studied Maths
8. (Original post by SeanFM)
Yes you'll see that fits into 2 < 8^x < 16 so it must be correct

I'm sure you'd ace it if you studied Maths

never, im only doing core maths for the sake of it ahaha

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Updated: October 2, 2016
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