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# Trig Identities help

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Why bother with a post grad? Are they even worth it? Have your say! 26-10-2016
1. Hey guys,

I'm a little stuck as to how to complete this.

I've gotten up to (1-cos^2x)/cos^2 - 1 but can't seem to work out the rest

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2. Try working with the LHS to produce something that you can manipulate using the
3. (Original post by TheBBQ)
Try working with the LHS to produce something that you can manipulate using the
I have no idea what that's meant to mean. (Self-teaching noob to maths)

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4. (Original post by nemanuel96)
I have no idea what that's meant to mean. (Self-teaching noob to maths)

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LHS = Left hand side of the equation.
See what you can do with that first
5. (Original post by TheBBQ)
LHS = Left hand side of the equation.
See what you can do with that first
Haha I know what that means. The mar scheme's next step is:

1/cos^2x - cos^2x/cos^2x - 1

But I'm not entirely sure how they've managed to do this. ☹️

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6. (Original post by nemanuel96)
Hey guys,

I'm a little stuck as to how to complete this.

I've gotten up to (1-cos^2x)/cos^2 - 1 but can't seem to work out the rest

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Just a hint,

So use this in reverse
7. (Original post by asinghj)
Just a hint,

So use this in reverse
Thanks a lot! It makes much more sense now

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8. I've gotten up to this question:

I've so far managed to get up to sinx/cosx + cosx/sinx

The mark scheme's next steps:

I don't understand how they've transitioned from what I've gotten up to, to getting sinx^2 + cosx^2/sinxcosx. Did they square both numerator and denominator to get to there?

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9. (Original post by nemanuel96)
I've gotten up to this question:

I've so far managed to get up to sinx/cosx + cosx/sinx

The mark scheme's next steps:

I don't understand how they've transitioned from what I've gotten up to, to getting sinx^2 + cosx^2/sinxcosx. Did they square both numerator and denominator to get to there?

* * *Posted from TSR Mobile
they just applied the method of adding fractions a/b + c/d = ( ad + bc *)/bd
10. (Original post by the bear)
they just applied the method of adding fractions a/b + c/d = ( ad + bc *)/bd
Thank you so much. Haha, my maths is a little rusty.

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