Trigonometry Identities
prove:
cosecx / cosecx - sinx = sec^2x
LHS= (1/sinx)/ (1/sinx)-sinx/1
= sinx/ sin2x
= (1-cos^2x)^1/2 / (1- cos^2x)
= (1-cos^2x)^-1/2
where do i go from here?
cosecx / cosecx - sinx = sec^2x
LHS= (1/sinx)/ (1/sinx)-sinx/1
= sinx/ sin2x
= (1-cos^2x)^1/2 / (1- cos^2x)
= (1-cos^2x)^-1/2
where do i go from here?
Original post by Custardcream000
prove:
cosecx / cosecx - sinx = sec^2x
LHS= (1/sinx)/ (1/sinx)-sinx/1
= sinx/ sin2x
= (1-cos^2x)^1/2 / (1- cos^2x)
= (1-cos^2x)^-1/2
where do i go from here?
cosecx / cosecx - sinx = sec^2x
LHS= (1/sinx)/ (1/sinx)-sinx/1
= sinx/ sin2x
= (1-cos^2x)^1/2 / (1- cos^2x)
= (1-cos^2x)^-1/2
where do i go from here?
= sinx/ sin2x
I'm not sure where this came from.
Try multiplying top and bottom of the fraction by sin(x) instead.
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