TMUA Preparation

Hi,

Is anyone else on here sitting the TMUA (Test for Mathematics Unviersity Admissions). Durham, Lancaster and LSE will all be using it for 2017 entry.

I quite like the style of the test, especially the second paper. How is everyone preparing for it? Anything besides working on the Specimen Paper?

Tbh I am pretty chilled about it. I have done some MAT papers to prep for it and some maths challenge. I recently did the specimen papers and got 37/40 over the two papers so I am happy atm.




Posted from TSR Mobile

Was that in timed conditions? Dont mean to be rude haha just want to know where i stand compared to everyone else considering theres no grades or grade boundaries??

Timed conditions. How did you do XD?

Ive only done the first specimen paper and got 7 out of 20 but i ended spending more time on the earlier questions and wasting time tbf. I think though it tests to see if you can see shortcuts almost and your intuition.

Have you looked at the enhanced specification? I found it particularly useful for paper 2.

I have had a quick look but not had chance to properly read through it yet. What i did read though was interesting. What did you study at as and your grades too if thats alright??

Sorry for late reply - was doing maths .
AS Grades: AAAAA (Maths[98%], Further Maths[98%], Physics, Chemistry and Electronics[99%]) and did (M2, M3 and M4 on top of this)
Predicted at A2: A*A*A*A*A* (Maths, Further Maths, Additional Further Maths, Physics and Electronics)

Have you looked at the enhanced specification? I found it particularly useful for paper 2.

crying with laughter

Just giving out advice...

Tbh I am pretty chilled about it. I have done some MAT papers to prep for it and some maths challenge. I recently did the specimen papers and got 37/40 over the two papers so I am happy atm.


Posted from TSR Mobile

Hey I was wondering if you could help me with q19 on paper 1? I can't get it and would appreciate any help

We know that $u_{1}=4, \enspace u_{2} = 4r \enspace \text{and} \enspace u_{4}=4r^{3}$. And that, as they form an arithmetic series, $4r^{3}-4r=4r-4$. Hence we obtain the equation $r^{3}-2r+1=0$.

Now, $r=1$ is a trivial solution to this cubic. Then we obtain $r^{3}-2r+1=(r-1)(r^{2}+r-1)=0$

Solving for $r$ gives $r=\frac{\sqrt{5}-1}{2}$

Subbing this into $S_{\infty}=\frac{4}{1-r}$ gives $S_{\infty}=2(3+\sqrt{5})$.

Hope this helps

It really does Thank you so much!

Hi,

Is anyone else on here sitting the TMUA (Test for Mathematics Unviersity Admissions). Durham, Lancaster and LSE will all be using it for 2017 entry.

I quite like the style of the test, especially the second paper. How is everyone preparing for it? Anything besides working on the Specimen Paper?