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Integrate this

[br][br]∫x+1x2+4x+5dx[br][br][br][br][br][br][br]\int \frac {x+1}{x^2+4x+5} dx[br][br][br][br][br]

Thank you :smile:
Original post by Maths6186a
[br][br]∫x+1x2+4x+5dx[br][br][br]\int \frac {x+1}{x^2+4x+5} dx[br]

Thank you :smile:


write it as ∫x+2x2+4x+5 dx−∫1x2+4x+5 dx \displaystyle \int \frac {x+2}{x^2+4x+5} \:dx - \int \frac{1}{x^2+4x+5} \: dx

left hand side is of the form k∫f′(x)f(x) \displaystyle k\int \frac{f'(x)}{f(x)} and right hand side can be done by completing the square and using a tan substitution
Original post by Maths6186a
[br][br]∫x+1x2+4x+5dx[br][br][br][br][br]\int \frac {x+1}{x^2+4x+5} dx [br] [br][br]

Thank you :smile:


But I don't want to integrate it :frown:
Reply 3
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alow
19
Ask WolframAlpha if you're too lazy to do it yourself.
Reply 4
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Maths6186a
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Original post by alow
Ask WolframAlpha if you're too lazy to do it yourself.


So me not knowing how to do something = me being to lazy to do it?
Original post by Maths6186a
So me not knowing how to do something = me being to lazy to do it?


Why are you doing a question where you have no idea how to approach it then?? Learn about these integrals first.
Original post by Maths6186a
So me not knowing how to do something = me being to lazy to do it?


No, you just said 'integrate this.' You didn't post any of your own ideas/attempts and did not mention where you were stuck. You're not asking for help; you're just asking for the whole solution. That is being lazy.
Reply 7
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Maths6186a
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Original post by RDKGames
Why are you doing a question where you have no idea how to approach it then?? Learn about these integrals first.


Sorry sir. Am I getting a detention now? :frown:
Reply 8
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Maths6186a
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Original post by IrrationalRoot
No, you just said 'integrate this.' You didn't post any of your own ideas/attempts and did not mention where you were stuck. You're not asking for help; you're just asking for the whole solution. That is being lazy.


I didn't mention where I was stuck because I had no idea how to do it from the beginning. I spent a good while failing to do the problem before posting on here. Silly billy.
Original post by Maths6186a
I didn't mention where I was stuck because I had no idea how to do it from the beginning. I spent a good while failing to do the problem before posting on here. Silly billy.


"You're not asking for help; you're just asking for the whole solution."

Anyway it's pretty sad that you post a thread demanding the complete solution to a problem and then you try to patronise the people who explain what's wrong with that.
Original post by IrrationalRoot
"You're not asking for help; you're just asking for the whole solution."

Anyway it's pretty sad that you post a thread demanding the complete solution to a problem and then you try to patronise the people who explain what's wrong with that.


not really

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