So I used F=MA equation, 12000 - 300g = n x 75g(a), where n stands for number of people. Then I divided the equation by 75g(3) to get n on its own, which got 4 people (1 s.f.) but the answer is 8. Can someone tell me what I'm doing wrong? Thanks.
No - you need to consider what will happen at the maximum acceleration, as this will correspond to the maximum tension in the cable, which you mustn't exceed.
Okay, let's do this the way it's supposed to be done.
You know that T<12000
⇒T−(300+75n)g<12000−(300+75n)g
⇒ma<9060−735g
Net force (ma) increases proportionally to the increase of acceleration, and since acceleration has an upper bound, take it to be the maximum in order to work out the maximum amount of people when the acceleration is maximum. So a=3.
Plug that into the inequality, plug the total mass in, solve the inequality for n.
A full solution would require me to finish off the question completely, clearly indicating each step, and doing it all for her with the correct answer at the end. I simply pushed her in the right direction by providing a decent start and hopefully making her understand where it all comes from and why. The other half of the solution is up to her to complete.
A full solution would require me to finish off the question completely, clearly indicating each step, and doing it all for her with the correct answer at the end. I simply pushed her in the right direction by providing a decent start and hopefully making her understand where it all comes from and why. The other half of the solution is up to her to complete.
pushed her to the point of simply needing to substitute values which you explicitly mentioned was necessary.
pushed her to the point of simply needing to substitute values which you explicitly mentioned was necessary.
Considering she went with a completely different method, it is safe to assume that throwing her into my method without much information wouldn't be beneficial whatsoever. I pushed her in the right direction by telling her what she needs to do, and showing half of it. Substituting values is the obvious part that I mentioned for the sake of understanding.
Considering she went with a completely different method, it is safe to assume that throwing her into my method without much information wouldn't be beneficial whatsoever. I pushed her in the right direction by telling her what she needs to do, and showing half of it. Substituting values is the obvious part that I mentioned for the sake of understanding.
What do you mean the other HALf, more like the other 1/100, literally called me out yesterday just so you could do the same thing, nice work
What do you mean the other HALf, more like the other 1/10, literally called me out yesterday just so you could do the same thing, nice work
I've seen a lot of solutions around this forum to see what counts as a full solution and what does not under different circumstances and contexts, hence why I called your solution out.
If you feel like it is too much information, then report it.
I've seen enough around this site to see what counts as a full solution and what does not under different circumstances and contexts, hence why I called your solution out.
If you feel like it is too much information, then report it.
why am i even doing this lol, I literally dont care
Okay, let's do this the way it's supposed to be done.
You know that T<12000
⇒T−(300+75n)g<12000−(300+75n)g
⇒ma<9060−735g
Net force (ma) increases proportionally to the increase of acceleration, and since acceleration has an upper bound, take it to be the maximum in order to work out the maximum amount of people when the acceleration is maximum. So a=3.
Plug that into the inequality, plug the total mass in, solve the inequality for n.
What am I doing wrong here? (12000-300g+9060+735g)/ -735 ?