A student hears 5.29 grams of Sr(No3)2 and collects the gas at RTP. 2Sr(No3)2 - 2SrO + 4NO2 + O2 Calculate the volume of gas in dm3 Molar mass of Sr(No3)2 = 211.6 g mol -1
A student hears 5.29 grams of Sr(No3)2 and collects the gas at RTP. 2Sr(No3)2 - 2SrO + 4NO2 + O2 Calculate the volume of gas in dm3 Molar mass of Sr(No3)2 = 211.6 g mol -1
Any ideas of how to do this?
First you need to calculate the number of moles of Strontium Nitrate in 5.29 grams
From the equation of the reaction you then know how many moles of gas are produced for each mole of nitrate reacting, so you can work out how many moles of gas are produced.
You can then use the ideal gas law to find the volume that this gas will occupy (or if you prefer you can use the fact that one mole of gas at RTP occupies 24000cm^3)