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Maths urgent help?

I know that if a function is even when g(-x) = g(x) and odd when g(-x) = -g(x)
However, I don't know what trigonometry identity to use to solve Q2(c).

https://gyazo.com/91bf748848940f231bf1dbf2692bf436


Also, I don't know how to go about solving Q3(b)

https://gyazo.com/464ec108aa3cea10d3ef8140bea1f8ad


Any help/guidance would be appreciated. :hmmmm2:
(edited 7 years ago)
Original post by XxKingSniprxX
I know that if a function is even when g(-x) = g(x) and odd when g(-x) = -g(x)
However, I don't know what trigonometry identity to use to solve Q2(c).

https://gyazo.com/91bf748848940f231bf1dbf2692bf436


Also, I don't know how to go about solving Q3(b)

https://gyazo.com/464ec108aa3cea10d3ef8140bea1f8ad


Any help/guidance would be appreciated. :hmmmm2:


For Q2(c), draw a graph of the function, the answer should then be obvious.

For Q3(b), let h(x) = f(x) g(x). Then h(-x) = f(-x)g(-x). Now go through the cases of what happens to f(-x) and g(-x).
Original post by XxKingSniprxX
I know that if a function is even when g(-x) = g(x) and odd when g(-x) = -g(x)
However, I don't know what trigonometry identity to use to solve Q2(c).

https://gyazo.com/91bf748848940f231bf1dbf2692bf436


Also, I don't know how to go about solving Q3(b)

https://gyazo.com/464ec108aa3cea10d3ef8140bea1f8ad


Any help/guidance would be appreciated. :hmmmm2:


For your first part there were not many trig identities from A-level that you learnt, there are only so many that you can use... so think about each one and see which one will get you to what you are trying to prove.
My guess would be the addition formula: cos (a - b) = cos(a)cos(b) + sin(a)sin(b).

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