Yes, it's what you get when you complete the square on the equation ax^2 + bx + c = 0. Hence, you substitute your values for a, b and c (e.g. a=3, b=2 and c=-1 for 3x^2 + 2x - 1 = 0) to find the solutions of the equation.
Note that b^2 - 4ac >= 0 for there to be ('real') solutions (since you can't square root a negative number).