Help needed!!!!
University course discussion for Pharmacy.
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Help needed!!!!
If you were asked to prepare 500 mL of a 100 M stock solution of drug Y (molecular
weight 180), calculate how many milligrams of drug Y you
would need to weigh out in order to make this solution. SHOW YOUR
CALCULATIONS.
Can anyone help on the above question??
I'm really stuck and need help as I have a resit coming up
thanksxxx -
Re: Help needed!!!!(Original post by Cetomacrogol)
9 mg
calculations:
M= 180 g/mol
V=500ml= 0,5 dm~3
c= 0,0001 M/ dm~3
quantity (in moles) of drug Y in 0,5 dm3 of the solution:
x= 0,0001 mol * 0,5 dm~3
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1dm~3
x= 0,00005 mol
mass of drug Y in o,5 dm~3 of the solution:
m= 0,00005 mol * 180g/mol = 0,009g= 9mg