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AQA - Module 4 - Kp calcs questions - help please

Hi can anyone help with these please.

C2H4(g) + H20(g) ----> C2H5OH(g)
Under standard conditions (10^5Pa, 25 dedgrees cent), 1 mole of each pof the reactants produces 0.739 moles of ethanol in equilibriam. Calculate Kp.

I got the answer to be 43.4 but I was wondering if I was right.

Thanks :smile:
Reply 1
Avatar for RHCPfan
RHCPfan
OP
12
Another quick question

If there are 0.812 mole of ethanol at equilibrim calculate the number of moles of reactants at eq. Assume there was 1 mol of each to begin with.

would I start this by doing 1 - 0.812?
if so what would be the next step
thanks
Reply 2
Avatar for Wangers
Wangers
16
Write what you have done.

Remember the equilibrium equations, and remember to use the right units.

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