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OCR B MATHS 25th MAY PAPER 4 CALC UNOFFICIAL MARK SCHEME

What answers

How was the paper??

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For the first question I got the answer: 3
I believe it was [2 Marks]
Original post by JackMoseley
For the first question I got the answer: 3
I believe it was [2 Marks]


Same and the LCM was 2520 I think
Original post by Anand3761
What answers

How was the paper??


It went so good I'm so happy with it
Original post by studiousninja
Same and the LCM was 2520 I think


Exactly what I got - checked it online and got the same result.

Question was: What is the LCM of 180 and 504
The completing the square was (x+5)^2-9
Original post by studiousninja
The completing the square was (x+5)^2-9


It was (x-5)^2-9

The original equation was x^2-10x+16
Reply 7
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Anand3761
OP
13
What did you guys get for the perimeter

I got 172 as

The length of the rectangle was 120 + 120 + (60- it was a semicircle so the height was the circles radius- 60) +60 = 360

Semi circle perimeter = pi d = 120 pi /2 =60 pi

360-60pi = 171.5 (3 s f) - 172
The claim about the car travelling at 60mph was false, was actually 67.5mph
Reply 9
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Anand3761
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13
The rotations were easy-

The bearings was ok-

135
209. Something or that about

I thought the MpH was lower

They needed speed cameras

34.5 for the pressure one
Reply 10
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Anand3761
OP
13
Original post by studiousninja
The claim about the car travelling at 60mph was false, was actually 67.5mph


It added up so that dust was 102 m-
And mph was 58. Something
Reply 11
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Anand3761
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13
Describe the graph of x2 + y2 =9

I said y intercept of 3

X- intercept of -3 and 3

Smiley face graph
Original post by studiousninja
The claim about the car travelling at 60mph was false, was actually 67.5mph


but the claim was that it reached 60mph within 10 seconds so wouldnt the claim be true because it did reach 60mph within the 10 seconds
Reply 13
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Anand3761
OP
13
Haredst question-
Give me one or two and I'll give my answers
Original post by Anand3761
What did you guys get for the perimeter

I got 172 as

The length of the rectangle was 120 + 120 + (60- it was a semicircle so the height was the circles radius- 60) +60 = 360

Semi circle perimeter = pi d = 120 pi /2 =60 pi

360-60pi = 171.5 (3 s f) - 172


I worked out the curved part by working out circumference of the circle and dividing by 4 as it was 1/4 so 120pi/4 =30pi and then added the other sides which were 60 each so added up to 120 and then 30pi + 120 =214.25
Original post by sarrraaaaaa
but the claim was that it reached 60mph within 10 seconds so wouldnt the claim be true because it did reach 60mph within the 10 seconds


Oh yeah oh no, that will only cost me one mark that's alright
Reply 16
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Anand3761
OP
13
Original post by studiousninja
I worked out the curved part by working out circumference of the circle and dividing by 4 as it was 1/4 so 120pi/4 =30pi and then added the other sides which were 60 each so added up to 120 and then 30pi + 120 =214.25


If it was out of 5, how many marks would my method get?
Reply 17
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Anand3761
OP
13
Original post by studiousninja
Oh yeah oh no, that will only cost me one mark that's alright


What did the q involve again?
Original post by Anand3761
What did the q involve again?


It was that question with the graph of the car going to 30m in 10secs, you had to convert the 10s into hours, that one
Original post by sarrraaaaaa
but the claim was that it reached 60mph within 10 seconds so wouldnt the claim be true because it did reach 60mph within the 10 seconds


Yeah that's what I thought

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