Boric Acid Equilibriums

I've been given the equilibrium

H3BO3 (reversible reaction sign) H+ + H2BO3 -

and I have to give two other equilibria which could be formed. I haven't really got a clue what I'm doing so I've guessed the following:-

H3BO3 (reversible reaction sign) H2O + HBO2

H3BO3 (reversible reaction sign) H2O3 + HB

I really don't have a clue if these are correct, and I highly doubt the compounds I've put down exist! (well, i know H20 and H2O3 do, but I'm not sure about the others!)

Any advice would be much appreciated! Thanks

Reply 1

Wangers

Think about water, and what H+ is....

Reply 2

mooseisabunny

and for future reference it is equilibria...

Reply 3

Mist

H3BO3 ----> H2BO3- + H+

H2BO3- -----> HBO3(2-) + H+

HBO3(2-) ------> BO3(3-) + H+

H3BO3 is a triprotic acid, and can therfore lose up to 3 protons..., in the equations above :smile:

all these are reversible, just I dont have reversible reaction sign.. :frown:

Reply 4

Wangers

Mist

H3BO3 ----> H2BO3- + H+

H2BO3- -----> HBO3(2-) + H+

HBO3(2-) ------> BO3(3-) + H+

H3BO3 is a triprotic acid, and can therfore lose up to 3 protons..., in the equations above :smile: