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Help please....

hello...just wondering if anyone could tell me the combustion formula for butan-1-ol ( is it C4H9OH + 7.5O2 --> 5CO2 + 6H2O) and propan-2-ol.
Also when working out enthalphy change using bond enthalpies would propan-1-ol and propan-2-ol have the same?

thanks in advance
x
google 'butan-1-ol properties' or 'enthalpy of combustion' of same .... it's not rocket science.

part 2 - yes the same bonds are broken and formed
it's C4H9OH + 6.5O2 --> 4CO2 + 5H2O

this is how to remember it:
The number of moles of CO2 will be the number of carbon atoms there are in the equation.
example - there are 4 carbons, so there are four moles of carbon dioxide

The number of moles of water will be half the number of hydrogen atoms.
example - there are 10 hydrogen atoms, so there are five moles of water.

then you just count the number of oxygens and figure out the number of moles accordingly :smile:

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