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Edexcel Statistics S1 Exam Jan 2008

Reply 80

edward_wells90

Does anyone remember what they put down for the regression question?

What was your y=mx+c ?

Reply 81

M.A.H

17

i wrote its a weak correlation, no set pattern and waffled about other stuff

Reply 82

Alessandro_22

8

i dont understand for the histogram if you got 12 as your final answer then frequency density was 1.2, didnt look anywhere near over one on the graph or was the graph not accurate?

Reply 83

M.A.H

17

edward_wells90

Does anyone remember what they put down for the regression question?

What was your y=mx+c ?

8.89 n 7.73 or something

Reply 84

Ar5enal Fan

OP

10

gj3

i dont understand for the histogram if you got 12 as your final answer then frequency density was 1.2, didnt look anywhere near over one on the graph or was the graph not accurate?

Apparantly if you worked out the frequencies for all the other groups as well it came to 70 and the question said that there were 140 runners, so you had to multiply it by 2 to get the actualy number of runners. I done 6, but I think the answer would be 12 because they wouldn't make a 5 mark question that easy!

Reply 85

Alessandro_22

8

y= -200 sumfin + sumfin x

Reply 86

Ribulose Bisphosphate

2

for the regression i got something like:

y = 8.something + 7.73x ... anyone else get that???

Reply 87

Ar5enal Fan

OP

10

TaChYcArDiA

for the regression i got something like:

y = 8.something + 7.73x ... anyone else get that???

Yh I got that

Reply 88

Ribulose Bisphosphate

2

M.A.H

8.89 n 7.73 or something

yo yo i got that too!! BRAP BRAP!!!

guess i'm retaking

Is anyone else really pissed off @ the histogram question?

Cuz never in my life have I seen a question like that, its ALWAYS frequency = freq. density x class width. Thats the whole bloody point of a histogram! Its not supposed to be like, work out the frequency for the every box and then find that value, then we have to make it proportional to the total frequency, thus every frequency in each box also has to be multiplied... blah blah blah thats a screwed up question!

Yes i put down 6.

Reply 91

Alessandro_22

8

how many marks do you need for a B

Reply 92

Ar5enal Fan

OP

10

edward_wells90

Is anyone else really pissed off @ the histogram question?

Cuz never in my life have I seen a question like that, its ALWAYS frequency = freq. density x class width. Thats the whole bloody point of a histogram! Its not supposed to be like, work out the frequency for the every box and then find that value, then we have to make it proportional to the total frequency, thus every frequency in each box also has to be multiplied... blah blah blah thats a screwed up question!

Yes i put down 6.

Yh, I don't think that question was fair either. I haven't ever come across a question like that in the edexcel textbook or past exam question so I just left the answer as 6 because f.d x class width should equal frequency. But well done to the people who got it right! :smile:

Reply 93

M.A.H

17

edward_wells90

Is anyone else really pissed off @ the histogram question?

Cuz never in my life have I seen a question like that, its ALWAYS frequency = freq. density x class width. Thats the whole bloody point of a histogram! Its not supposed to be like, work out the frequency for the every box and then find that value, then we have to make it proportional to the total frequency, thus every frequency in each box also has to be multiplied... blah blah blah thats a screwed up question!

Yes i put down 6.

looooooooooool yup i got 6 too didnt realise, i didnt even read the Q properly (I blame tooo many past papers)

Reply 94

Ribulose Bisphosphate

2

the whole point of that question was to test if people realised that the area under the histogram is proportional to the frequency the histogram represents or displays...if this was your first line of working then all the other steps flowed from it...

Reply 95

Ar5enal Fan

OP

10

gj3

how many marks do you need for a B

53 I think

Reply 96

muell

Hi,

125, 160, 169, 171, 175, 186, 210, 243, 250, 258, 390, 420
these are the values after sorting them out (I think)

to work out the right term for q1 = (1/4)*12 = 3
3 is an intenger
therefore you take the average value of the third and the fourth term
so 0.5*(169+171)= 170
so q1= 170

I ve used similar methods to work out the other quartiles:
q2= 198
q3= 254

I am not sure if this is correct but that is how i did it :smile:

might be wrong though :p: