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Edexcel C4 Partial Fractions

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    Please can someone explain the working to Exercise 1D/8 at the foot of page 5 in the Heinemann C4 book?

    Many thanks.
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    Why don't you post the question and/or working?
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    (x^2+ 5x+7)/(x+2)^3 becomes 1/(x+2) + 1/(x+2)^2 + 1/(x+2)^3

    I'd appreciate it if someone could tell me how this is done. Thank you.
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    If you have

    \frac{x^2 + 5x + 7}{(x+2)^3}

    Then the partial fractions are

    \frac{x^2 + 5x + 7}{(x+2)^3} = \frac{A}{(x+2)} + \frac{B}{(x+2)^2} + \frac{C}{(x+2)^3}.

    Likewise, if it were

    \frac{x^2 + 5x + 7}{(x+2)^4}

    You'd want

    \frac{x^2 + 5x + 7}{(x+2)^4} = \frac{A}{(x+2)} + \frac{B}{(x+2)^2} + \frac{C}{(x+2)^3} + \frac{D}{(x+2)^4}

    It's just a standard pattern you should learn.

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Updated: February 20, 2008
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