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Chemistry Question

Can anyone tell me whther the following are reduction or oxidation:

[CuCl4]2- going to [CuCl2]-

and [MnO4]- going to [Mn]2+

Thanks
First one is loss of negative charge, so is oxidation, and the second one is oxidation too. I think that's right...?
Work out the total oxidation states involved, for both before and after, and then see if it goes up or down.
Reply 3
Avatar for ooze
ooze
13
flown_muse
First one is loss of negative charge, so is oxidation, and the second one is oxidation too. I think that's right...?

Nope, the metal is reduced in both :tongue:
Reply 4
Avatar for necevans
necevans
First one is Cu2+ --> Cu+ = reduction. (ie gain of electrons or decreasing oxidation no.)

Second on is Mn as +7 --> Mn2+ = reduction for same reasons
Reply 5
Avatar for elimy_1990
elimy_1990
i was taught using OILRIG:

Oxidation
Is
Loss so if the charge gets more positive

Reduction
Is
Gain so if the charge gets more negative

hope that helps
Reply 6
Avatar for Malsy
Malsy
18
..
Tanya4
Can anyone tell me whther the following are reduction or oxidation:

[CuCl4]2- going to [CuCl2]-

and [MnO4]- going to [Mn]2+

Thanks


[CuCl4] 2-
Oxidation state of copper = +2
Cl = -1

[CuCl2]-
Oxidation state of copper = +1
Cl = -1

Decrease, so GAIN of ELECTRONS. Reduction.

===========

[MnO4]-
Oxidation state of Mn = +7
Oxygen = -2

[Mn]2+
Mn = 2+

Decrease again, gain of electrons. Reduction.

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