In oxidation number questions, only a small number of elements have a fixed oxidation number regardless of where they are on the periodic table. Sulphur isn't one of them Oxygen is however, it is always -2.
In oxidation number questions, only a small number of elements have a fixed oxidation number regardless of where they are on the periodic table. Sulphur isn't one of them Oxygen is however, it is always -2.
Fair enough, i understand now, the question gave me firstlt H2SO4 and so im guessing that i had to find the ox number of sulphur = +6 and so i then had to realise that this ox number stays the same in the equation; this would give me; Cu= -(+6-8) Cu= -(-2) Cu=+2