Official TSR Mathematical Society
Maths and statistics discussion, revision, exam and homework help.
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Re: Official TSR Mathematical SocietyIt also does stuff like complex numbers and matrices (I think) which is a godsend.(Original post by Tobedotty)
the silver casio one, I think its called the fx-991es. Its basically just an upgraded version of the fx83 and has a couple of handy buttons that can work out definite integrals and the gradient of a line at a particular point, since only does definite things its not banned but its probably the most sophisticated one you'll find that isnt banned. -
Re: Official TSR Mathematical SocietyThanks for the input, I've looked it up and it looks really good, problem solved>>(Original post by Tobedotty)
the silver casio one, I think its called the fx-991es. Its basically just an upgraded version of the fx83 and has a couple of handy buttons that can work out definite integrals and the gradient of a line at a particular point, since only does definite things its not banned but its probably the most sophisticated one you'll find that isnt banned. -
Re: Official TSR Mathematical SocietyI'm by no means an expert but, surely, (¬Y)^Y is the empty set. Where is the contradiction?(Original post by Blutooth)
as (¬Y)^Y is a contradiction (X OR ¬Y) ^Y must = X^Y -
Re: Official TSR Mathematical SocietyAs they are propositions it is a contradiction...e.g. let Y be the proposition that I am a cat...I cannot be both a cat and not a cat simultaneously...(Original post by ben-smith)
I'm by no means an expert but, surely, (¬Y)^Y is the empty set. Where is the contradiction?
Spoiler:Show...barring some strange quantum effect
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Re: Official TSR Mathematical SocietyWhy do you think y^(¬Y) would be the empty set?(Original post by ben-smith)
I'm by no means an expert but, surely, (¬Y)^Y is the empty set. Where is the contradiction?
Let us assume that y is the empty set, are you telling me that (¬Y) is also the empty set? Surely not. (¬Y) in this case would be something other than the empty set? not the empty set and the empty set is a contradiction (and not the empty set).
Last edited by Blutooth; 26-03-2012 at 22:25. -
Re: Official TSR Mathematical Societyerrr, well don't view them as propositions(Original post by TheMagicMan)
As they are propositions it is a contradiction...e.g. let Y be the proposition that I am a cat...I cannot be both a cat and not a cat simultaneously...
Spoiler:Show...barring some strange quantum effect

I guess my point is that if it were a contradiction then the whole initial statement would be a contradiction in which case we aren't really doing anything. Anyway, it was a minor point (if one at all).
No idea why someone negged you. Let me try and balance it out. -
Re: Official TSR Mathematical SocietyIf we look at it from a set point of view, aren't we just going to use the fact that taking the union of a set A with the empty set is equivalent to A(Original post by ben-smith)
errr, well don't view them as propositions
I guess my point is that if it were a contradiction then the whole initial statement would be a contradiction in which case we aren't really doing anything. Anyway, it was a minor point (if one at all).
No idea why someone negged you. Let me try and balance it out. -
Re: Official TSR Mathematical SocietySorry, I negged him by accident, but I dont have any rep points so it wont affect your score!(Original post by ben-smith)
errr, well don't view them as propositions
I guess my point is that if it were a contradiction then the whole initial statement would be a contradiction in which case we aren't really doing anything. Anyway, it was a minor point (if one at all).
No idea why someone negged you. Let me try and balance it out. -
Re: Official TSR Mathematical SocietyWell, my thinking is that ¬Y is the complement of Y and so they are disjoint and therefore, by definition, their Y^(¬Y)= ∅.(Original post by Blutooth)
Why do you think y^(¬Y) would be the empty set?
Let us assume that y is the empty set, are you telling me that (¬Y) is also the empty set? Surely not. (¬Y) in this case would be something other than the empty set? not the empty set and the empty set is a contradiction (and not the empty set).
Maybe we have different interpretations of what this means, I mean it in the way this does. -
Re: Official TSR Mathematical SocietyThat's what I was trying to say!(Original post by TheMagicMan)
If we look at it from a set point of view, aren't we just going to use the fact that taking the union of a set A with the empty set is equivalent to A -
Re: Official TSR Mathematical SocietyThere are different ways of interpreting the problem, I was just teasing you. But seriously, if you can tell me what ∅^(¬∅) equals, I will be impressed as I haven't the foggiest.(Original post by ben-smith)
Well, my thinking is that ¬Y is the complement of Y and so they are disjoint and therefore, by definition, their Y^(¬Y)= ∅.
Maybe we have different interpretations of what this means, I mean it in the way this does.
Last edited by Blutooth; 26-03-2012 at 23:11. -
Re: Official TSR Mathematical Society[Assuming these are curves in the real plane], writing(Original post by gff)
Here we go, a fun question.
[*] The curves
and
are defined in the plane as follows.




Prove that
.
gives new sets:




This gives that
and
are comprised of the zeros of
. Since we have a nice correspondence between
and
, we have
.
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Re: Official TSR Mathematical SocietyI was hoping it's gonna stay for a while...(Original post by Unbounded)
...
+rep
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Re: Official TSR Mathematical SocietyHere's a nice question:
i)Take 4 quantities
,
.
We play a game according to these rules: Player A adds a total of 1 to the quantities, apportioning it however he likes. Player B then reduces any two consecutive quantities, or the first and the last, to 0. They then alternate 'turns'. Assume Player B plays optimally. Player A wins if he makes any one of the quantities greater than a certain value
. Player B's goal is to stop Player A from winning. The game continues indefinitely. What is the maximum value of
such that Player A can win?
ii) Using the same rules, what is the maximum value of
if there are 5 quantities?
iii) And if there are
quantities?
I have a very ugly and lengthy solution for iii) so bonus points for elegance on that oneLast edited by TheMagicMan; 28-03-2012 at 14:22. -
Re: Official TSR Mathematical SocietyBefore I potentially waste a lot of time doing it all wrong, is the answer to i)(Original post by TheMagicMan)
~Quantity question^
Spoiler:Show
16/3 (i.e. this is the maximum value for 4 quantities)?



