[King-Panther]

(Original post by raheem94)
Yes, you did it correctly and got the correct answer .

What would I sub in to get 0? Or do I not have to do that??

[King-Panther]

(Original post by raheem94)
Yes, you did it correctly and got the correct answer .

Thats the piece of work I'm doing, for future reference.

[raheem94]

(Original post by King-Panther)
What would I sub in to get 0? Or do I not have to do that??

I have seen the microsoft word file. You question is done, you don't need to do anything further.

[King-Panther]

(Original post by raheem94)
I have seen the microsoft word file. You question is done, you don't need to do anything further.

The next question, I got dy/dx = 12x + 5

So when gradient is 13, I did

13 = 12x + 5

which is x = 2/3



I dont understand Q)15.

[raheem94]

(Original post by King-Panther)
The next question, I got dy/dx = 12x + 5

So when gradient is 13, I did

13 = 12x + 5

which is x = 2/3

You are starting to grasp the concepts .

This is correct as well, i also get the same answer.

[King-Panther]

(Original post by raheem94)
You are starting to grasp the concepts .

This is correct as well, i also get the same answer.

I know how to do them, I just didn't understand the wording..

I don't understand what they want for Q)15

[raheem94]

(Original post by King-Panther)
I dont understand Q)15.

Do you know integration?

[King-Panther]

(Original post by raheem94)
Do you know integration?

Yeah

I got x^4-x-2

Also, what is d2y/dx2 of x^2+2+1/x^2

[raheem94]

(Original post by King-Panther)
Yeah

I got x^4-x-2

So you got, , right?

But we need to add a constant of integration, c, because it is a indefinite integral.

So

Now use the conditions given in the question of y=17 and x=2 to find the value of 'c'.

[Zuzuzu]

(Original post by King-Panther)
Yeah

I got x^4-x-2

+c

Then sub in the numbers as given in the question.

You're probably best off creating your own thread for these questions.

[King-Panther]

(Original post by raheem94)
So you got, , right?

But we need to add a constant of integration, c, because it is a indefinite integral.

So

Now use the conditions given in the question of y=17 and x=2 to find the value of 'c'.

So 17=2^4-2^-2+c

Also, what is d2y/dx2 of x^2+2+1/x^2

[King-Panther]

(Original post by Zuzuzu)
+c

Then sub in the numbers as given in the question.

You're probably best off creating your own thread for these questions.

I did, but it was suggested this was the best place for me...

[raheem94]

(Original post by King-Panther)
So 17=2^4-2^-2+c

Also, what is d2y/dx2 of x^2+2+1/x^2

Sub in y=17 and x=2 in the above expression, to find the 'c'.


So

You don't need to find d2y/dx2.

[King-Panther]

(Original post by raheem94)


Sub in y=17 and x=2 in the above expression, to find the 'c'.


So

You don't need to find d2y/dx2.

Also, what is d2y/dx2 of x^2+2+1/x^2

Also, how about Q)16, b? Do I treat it as a quadratic?

I really appreciate this!

[raheem94]

(Original post by King-Panther)
I did, but it was suggested this was the best place for me...

Its better you use your previous thread, 'integration', or make a new thread don't post in this thread.

[raheem94]

(Original post by King-Panther)
Also, what is d2y/dx2 of x^2+2+1/x^2

Also, how about Q)16, b? Do I treat it as a quadratic?

I really appreciate this!

Treat 16b as a quadratic. And please don't post in this thread, use your previous thread again or make a new thread.

[King-Panther]

Can anyone help me?

http://www.thestudentroom.co.uk/show...1960422&page=7

[getoom]

help please?

http://www.thestudentroom.co.uk/show....php?t=1970327

[Dadeyemi]

Question: If you choose an answer to this question at random, what is the probability that you will be correct?
a. 25%
b. 50%
c. 0%
d. 25%

[Mc^3]

(Original post by Dadeyemi)
Question: If you choose an answer to this question at random, what is the probability that you will be correct?
a. 25%
b. 50%
c. 0%
d. 25%

e. mumble something vague about an ill-defined probability space and then regard the question with aloof disdain, claiming to have answered it fully and for it to be "trivial"

Spoiler:

Show

Or at least that's what Grimmett taught our year