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# Official TSR Mathematical Society Tweet

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1. Re: Official TSR Mathematical Society

How can we prove this?
2. Re: Official TSR Mathematical Society
(Original post by ambience)

How can we prove this?
Induction, probably and then using IBP? Not sure though - I'd need to actually try it

EDIT: Yep that comes out pretty easily using induction and IBP
Last edited by Intriguing Alias; 14-06-2012 at 00:41.
3. Re: Official TSR Mathematical Society
Can someone help me with this maths problem or know anyone that can. thank you :-)
In steady state heat transfer the temperature T satisfies the Laplace equation. In two dimensions with Cartesian coordinates x and y this equation is d2T/dx2 +d2T/dY2=0
This is a partial differential equation, and general methods of solving it are beyond the scope of this module - wait for the second and final year! However there are ways of getting an approximate solution to the equation by realising that it is a mathematical statement of the law of conservation of energy - in this case heat energy. One such method is the finite difference method.

One way to see how such methods work, is to consider a square area ABCD of a heat-conducting plate:

Figure 1
The values T0, T1, T2, T3, and T4 represent respectively the temperatures at the central point (or node) and the four surrounding equally distant nodes. T0 is at the centre of the sqaure, T1 goes through the middle of the points AD and conects to T0 on the sqaure. T3 goes through the middle ofthe points CB and connects to T0. T2 goes through the middle of the points DC and connects to T0 and T4 goes through the middle of the points AB and connects to T0. For the sake of simplicity suppose the length of side of the square is h, and that each of the temperature nodes are a distance h apart.

The law of conservation of energy in this case says that the net heat flowing into ABCD must equal the net heat flowing out. The heat flowing across a boundary of ABCD is proportional to the temperature gradient and the length of that boundary. Thus conservation of energy says
Heat in + Heat in = Heat out + Heat out
across AC across CD across AB across BD

Approximately this gives
(T0-T1/h)h +(T0-T4/h)h = (T2-T0/h)h+(T3-T0/h)h
or rearranging T0=1/4(T1+T2+T3+T4) .
ie temperature at one node = average of temperatures at four surrounding nodes.
Why is this approximate, and how can it be made more accurate? Write some words on this, and to see if you’ve really understood, do the following:
Work out the equation when ABCD is a rectangle but not necessarily a square, with the lengths
AB = CD = distance from T1 to T0 = distance from T0 to T3 = h
and the lengths
AC = BD = distance from T4 to T0 = distance from T0 to T2 = k

A simple case
A flat plate as shown in Figure 2 has the temperature on three edges held at T = 0; the left hand side and the top and bottom the fourth edge is held at a temperature of T = 100, which is on the right hand side. T1 and T2 are on the central nodes of the grid.
Figure 2

An approximate value of the temperature at certain points can be obtained as follows:
• Place a regular square grid over the plate as shown.
• Name the temperatures at the two central nodes of the grid T1 and T2.
• Then according to the finite difference model above, the values of T1 and T2, which are approximate values of the temperature at those points, can be found by noting that the temperature at each node is the average of the temperatures at the four surrounding nodes.

This results in two simultaneous equations which can be solved for T1 and T2. The equations are:
T1=(0+0+0+T2)/4and T2=(0+0+100+T1)/4

Solve these equations in two ways. Verify your answers.
4. Re: Official TSR Mathematical Society
(Original post by ambience)

How can we prove this?
u = -log x

Get
5. Re: Official TSR Mathematical Society
(Original post by Maths boy)
Can someone help me with this maths problem or know anyone that can. thank you :-)
In steady state heat transfer the temperature T satisfies the Laplace equation. In two dimensions with Cartesian coordinates x and y this equation is d2T/dx2 +d2T/dY2=0
This is a partial differential equation, and general methods of solving it are beyond the scope of this module - wait for the second and final year! However there are ways of getting an approximate solution to the equation by realising that it is a mathematical statement of the law of conservation of energy - in this case heat energy. One such method is the finite difference method.

One way to see how such methods work, is to consider a square area ABCD of a heat-conducting plate:

Figure 1
The values T0, T1, T2, T3, and T4 represent respectively the temperatures at the central point (or node) and the four surrounding equally distant nodes. T0 is at the centre of the sqaure, T1 goes through the middle of the points AD and conects to T0 on the sqaure. T3 goes through the middle ofthe points CB and connects to T0. T2 goes through the middle of the points DC and connects to T0 and T4 goes through the middle of the points AB and connects to T0. For the sake of simplicity suppose the length of side of the square is h, and that each of the temperature nodes are a distance h apart.

The law of conservation of energy in this case says that the net heat flowing into ABCD must equal the net heat flowing out. The heat flowing across a boundary of ABCD is proportional to the temperature gradient and the length of that boundary. Thus conservation of energy says
Heat in + Heat in = Heat out + Heat out
across AC across CD across AB across BD

Approximately this gives
(T0-T1/h)h +(T0-T4/h)h = (T2-T0/h)h+(T3-T0/h)h
or rearranging T0=1/4(T1+T2+T3+T4) .
ie temperature at one node = average of temperatures at four surrounding nodes.
Why is this approximate, and how can it be made more accurate? Write some words on this, and to see if you’ve really understood, do the following:
Work out the equation when ABCD is a rectangle but not necessarily a square, with the lengths
AB = CD = distance from T1 to T0 = distance from T0 to T3 = h
and the lengths
AC = BD = distance from T4 to T0 = distance from T0 to T2 = k

A simple case
A flat plate as shown in Figure 2 has the temperature on three edges held at T = 0; the left hand side and the top and bottom the fourth edge is held at a temperature of T = 100, which is on the right hand side. T1 and T2 are on the central nodes of the grid.
Figure 2

An approximate value of the temperature at certain points can be obtained as follows:
• Place a regular square grid over the plate as shown.
• Name the temperatures at the two central nodes of the grid T1 and T2.
• Then according to the finite difference model above, the values of T1 and T2, which are approximate values of the temperature at those points, can be found by noting that the temperature at each node is the average of the temperatures at the four surrounding nodes.

This results in two simultaneous equations which can be solved for T1 and T2. The equations are:
T1=(0+0+0+T2)/4and T2=(0+0+100+T1)/4

Solve these equations in two ways. Verify your answers.
Create a thread and ask there, not here.
6. Re: Official TSR Mathematical Society
(Original post by ambience)

How can we prove this?

The substitution instantly renders the result you want.
7. Re: Official TSR Mathematical Society
Can someone explain to me how to calculate the ratios in this question, it shows the answer in the bottom table , not not actually how they arrived at the numbers, which is very frustrating.

http://imageshack.us/f/688/screenshot20120614at175.png/
8. Re: Official TSR Mathematical Society
(Original post by TickTackToe)
Can someone explain to me how to calculate the ratios in this question, it shows the answer in the bottom table , not not actually how they arrived at the numbers, which is very frustrating.

http://imageshack.us/f/688/screenshot20120614at175.png/
A ratio is a relationship between two numbers: how much bigger/smaller one is compared to the other. So the ratio of average sales price to the average production cost is simply:

Example: for 2010 the fraction will give you 4.3 (to one decimal place), which means the average sales price was 4.3 times more than the average production cost.
9. Re: Official TSR Mathematical Society
(Original post by TheMagicMan)

The substitution instantly renders the result you want.
Gut gemacht!
10. Re: Official TSR Mathematical Society
Does anyone have any new problems for people to try?
11. Re: Official TSR Mathematical Society
I've done my AS exams, and I'll be continuing A2 in lessons. I shall then be doing AS Further over the summer and up to Christmas, on my own. If I manage this, is it possible for me to carry on the full A2 Further? I.e. 3 more modules (independently) between Christmas and summer.
12. Re: Official TSR Mathematical Society
(Original post by MrBlueMo0n)
I've done my AS exams, and I'll be continuing A2 in lessons. I shall then be doing AS Further over the summer and up to Christmas, on my own. If I manage this, is it possible for me to carry on the full A2 Further? I.e. 3 more modules (independently) between Christmas and summer.
You should really be creating your own thread for this and not asking on here!
13. Re: Official TSR Mathematical Society
(Original post by nohomo)
Does anyone have any new problems for people to try?
Why not. It's a "free" world

where, m>1
14. (Original post by nohomo)
Does anyone have any new problems for people to try?
I do. But I'm afraid It's a bit so easy.

This was posted from The Student Room's Android App on my HTC Wildfire
15. (Original post by boromir9111)
Why not. It's a "free" world

where, m>1
Something along the lines of a x=u+1 sub and power series?

Ibp looks like a distinct possibility as well

This was posted from The Student Room's iPhone/iPad App
Last edited by TheMagicMan; 12-07-2012 at 23:36.
16. Re: Official TSR Mathematical Society
(Original post by boromir9111)
You should really be creating your own thread for this and not asking on here!
I'm not joking, I don't know how to create my own thread!

Plus I thought it was fairly relevant, but that doesn't matter.
17. Re: Official TSR Mathematical Society
Hi, I have a question. If I do engineering at undergraduate level and get a BEng degree, can I do a Masters in Maths (MSc) at a UK University? Any help would be hugely appreciated as I am not from the UK.
18. Re: Official TSR Mathematical Society
(Original post by boromir9111)
Why not. It's a "free" world

where, m>1
Any hints?
19. Re: Official TSR Mathematical Society
(Original post by nohomo)
Any hints?
Consider that

And

where is the Gamma function [google it].

I have essentially given the problem away, but oh well.
20. Re: Official TSR Mathematical Society
(Original post by boromir9111)
Why not. It's a "free" world

where, m>1
That looks tough.