The Student Room Group
Uni students - Complete our survey >>
Uni students - Complete our survey >>
Uni students - Complete our survey >>

Official TSR Mathematical Society

Scroll to see replies

Reply 1280
Avatar for Kolya
Kolya
17
Swayum
Yup :frown:. It's a known bug though so they ought to fix it soon (but they may not make it high priority since it affects just 1 forum mainly).
Clearly the phrase "lots of testing" means different things to different people.
I only spotted the bug on sunday night after I alerted them and the response I got was:

J
thanks good find, we'll get this sorted. But it may not be in place for launch. will be a priority for straight after however
Reply 1282
Avatar for Kolya
Kolya
17
The Muon
I only spotted the bug on sunday night after I alerted them and the response I got was:
Did you ask him what type of priority it is?
Kolya
Did you ask him what type of priority it is?

Nope, I shall post the question now.
Gimme some Latex
Reply 1285
Avatar for J
J
17
we'll get it fixed this evening, sorry its still screwed (latex i mean)
≡ \equiv
Reply 1287
Avatar for Kolya
Kolya
17
Seems to be working again: ∀ϵ∃δ(ϵ>0  ⟹  (δ>0∧∀x(∣x−aˉ∣>δ  ⟹  ∣ϕ(x)−ϕ(aˉ∣<ϵ)\forall \epsilon \exists \delta (\epsilon > 0 \implies (\delta > 0 \land \forall x(|x - \bar{a}| > \delta \implies |\phi (x) - \phi (\bar{a}| < \epsilon )
Does that mean the old latex formulas are all gone?

O∣∀NosO | \forall Nos
Reply 1289
Avatar for Swayum
Swayum
18
J
we'll get it fixed this evening, sorry its still screwed (latex i mean)


{!!T!!H!!A!!N!!K!!S!!}\begin{Bmatrix} & ! & \\ ! & \text{T} & ! \\! & \text{H} & ! \\! & \text{A} & ! \\! & \text{N} & !\\! & \text{K} & !\\! & \text{S} & !\\ & ! & \end{Bmatrix}
Find the generating function for the sequence whose nth n^{th} terms is n2 n^2 + find a third order homogeneous linear recurrence relation for this sequence - therefore find the sum of the infinite series nth n^{th} term is n22n \frac{n^2}{2^n}
DeanK22
Find the generating function for the sequence whose nth n^{th} terms is n2 n^2 + find a third order homogeneous linear recurrence relation for this sequence - therefore find the sum of the infinite series nth n^{th} term is n22n \frac{n^2}{2^n}


Spoiler

Reply 1292
Avatar for SimonM
SimonM
18
Dadeyemi

Spoiler



Yes
Reply 1293
Avatar for J
J
17
oh good, glad working again :smile:
J
oh good, glad working again :smile:


Except for that smiley, though.
Reply 1295
Avatar for J
J
17
yeah, fixing latex took longer than i hoped. Missing smilies should be back tonight along with time of quote and bullets
Woo.latex.is.back Woo. latex. is. back
(∀ϵ>0)(∃δ>0)(∀x)(0≤∣x−a∣<δ  ⟹  ∣f(x)−f(a)∣<ϵ)(\forall \epsilon > 0) (\exists \delta > 0) (\forall x) (0 \le | x - a | < \delta \implies | f(x) - f(a) | < \epsilon)

For some reason the Analysis I lecturer likes to call this Dalek language.
Reply 1298
Avatar for SimonM
SimonM
18
J
yeah, fixing latex took longer than i hoped. Missing smilies should be back tonight along with time of quote and bullets


How about the old latex?
Some latex is still not working for me. For example, in post 1325 in this thread, I get 'unparseable or potentially dangerous (etc.)", or is that actually supposed to happen?

Quick Reply

Related discussions

Latest

Trending

Trending

Articles for you