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Adje
rupertj: "Bob rolls a 6 before Sue."

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How do you calculate that?

Is this something taught in statistics A Level, out of curiosity?
It comes up in S1. (But you'll need a bit of C2 to work it out in this case.)
Adje
It comes up in S1. (But you'll need a bit of C2 to work it out in this case.)

Well I've self-taught C1 and C2, while I'm currently working through C3, but I'll probably do S1 next year when I start A Levels.

Could I ask which part of C2 this involves?

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Reply 1344
Adje

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Or not, if you use the recurrence I've shown
Whatever happened to the Academic Restructure that they were going to do?

They're like 2 weeks behind schedule on it. Just inquisitive.
Reply 1346
sohanshah
Whatever happened to the Academic Restructure that they were going to do?

They're like 2 weeks behind schedule on it. Just inquisitive.


It's going to be done soon I think. Acaila's been away and busy for a while which has caused the delay I believe. But she appears to be back now (dunno if she's busy or not though). It's hardly a priority since it's not like anyone's going to be using the exam forums right now anyway :tongue:.
Swayum
It's going to be done soon I think. Acaila's been away and busy for a while which has caused the delay I believe. But she appears to be back now (dunno if she's busy or not though). It's hardly a priority since it's not like anyone's going to be using the exam forums right now anyway :tongue:.


:eek:
When did you become a minimod
Reply 1348
Reply 1349
Ok I have a little poser for the TSR crew. This just popped into my head whilst I was strolling around town earlier, but due to pressing Tripos concerns I don't want to spend too long trying to solve it myself.

Ok, so I have numbers 1, 2, ..., n

there are n! arrangements of these n numbers.

I now create a list of numbers such that every arrangement of 1, 2, ..., n appears in the list

eg for n = 3 the list 1, 2, 3, 2, 1, 3, 2, 3, 1, 2 - the arrangements 123, 132, 213, 231, 312 and 321 all appear at some point in this list. This list has "length" of 10 numbers.

My question is, for any n, what is the shortest length my list can be?

I'm really not sure how difficult (or time-consuming!) a solution this would be, but I'm not keen to try myself because I have deadlines to meet and pizza parties to attend. Kudos (and rep?) to anyone who has a go.
Reply 1350

This might sound weird but when did you become a minimod? It's cool :grin:
Khodu
This might sound weird but when did you become a minimod? It's cool :grin:

5 days ago or so I believe.
Khodu
This might sound weird but when did you become a minimod? It's cool :grin:

check the link you just quoted :tongue:
Reply 1353
The Muon
check the link you just quoted :tongue:



Oh. My bad. :tongue:
Reply 1354
A complicated looking integral:

1xln(x)ln(ln(x)) dx\displaystyle \int \frac{1}{x\ln(x)\ln(\ln(x))}\ \mathrm{d}x
Swayum
A complicated looking integral:

1xln(x)ln(ln(x)) dx\displaystyle \int \frac{1}{x\ln(x)\ln(\ln(x))}\ \mathrm{d}x


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Swayum
A complicated looking integral:

1xln(x)ln(ln(x)) dx\displaystyle \int \frac{1}{x\ln(x)\ln(\ln(x))}\ \mathrm{d}x

nope i'm stumped :unsure:
sohanshah
nope i'm stumped :unsure:


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Swayum
A complicated looking integral:

1xln(x)ln(ln(x)) dx\displaystyle \int \frac{1}{x\ln(x)\ln(\ln(x))}\ \mathrm{d}x



he he I like that
Reply 1359
DeanK22

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+ c :mad:.

sohanshah
nope i'm stumped :unsure:


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