I don't know if I've already said this - but the papers I posted should give you adequate preparation for tomorrow's/Thursday's exam. Remember that exam boards often repeat experiments that have come up in previous years.
on the paper it says thetha initial = 85.0 degrees C and thetha final = 75.0 degrees C. Hence Detal thetha = 75-85 = -10 degrees C
Delta means "change", you just need the difference in the two values. It asks you to calculate the fall in temperature. It has fallen by 10 degrees not by -10 degrees.
Delta means "change", you just need the difference in the two values. It asks you to calculate the fall in temperature. It has fallen by 10 degrees not by -10 degrees.
oohhh. Ic
Any ways even if u use +10degrees C as the change, i am gettin k= -1 in both part b) as c)
as delta thetha = k(thetha final - thetha initial)
10 = k(-10)
therefore k = -1
this is the same for part c.
And then part d says determine the percentage difference between your two values of k. I cant do that coz both the values of k that i got are -1 !
I also dun get this question on page 4 (same paper)
Explain carefully which of the circuits is the one you tested - I have no idea!
Okay, first you need to calculate the resistances for both connections. Then what you do is look at the three circuits, but imagine them being connected X to B and Y to A. When this is the case, wherever you see a diode, there will be no current in that part of the circuit.
Work out the total resistance for each circuit and see which one matches the resistance value you calculated for X to B and Y to A.
Okay, first you need to calculate the resistances for both connections. Then what you do is look at the three circuits, but imagine them being connected X to B and Y to A. When this is the case, wherever you see a diode, there will be no current in that part of the circuit.
Work out the total resistance for each circuit and see which one matches the resistance value you calculated for X to B and Y to A.