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Oxidation number of N in HNO3

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    ??? Can anyone helkp as to how they got the answer +5? I thought it would be -5.
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    3 oxygens at -2 each, one hydrogen (+1), so N must be +5 to sum to zero.
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    But the 3 oxygens are -6, plus the 1 from the hydrogen would have to make the N -5, not +5???
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    H = +1
    O x 3 = -2 x 3
    = -6
    net charge on molecule = 0

    So +1 -6 +N = 0
    => N = 0+6-1
    = +5
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    Oh wait I get it. Thanks!
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    (Original post by billykwok)
    H = +1
    O x 3 = -2 x 3
    = -6
    net charge on molecule = 0

    So +1 -6 +N = 0
    => N = 0+6-1
    = +5

    Bilbo - geek

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