C1 & C2 - EDEXCEL: 2nd June - ULTIMATE THREAD

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  1. Loz17's Avatar
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    Re: C1 & C2 - EDEXCEL: 2nd June - ULTIMATE THREAD
    yarrrp thank goodness...
  2. Inquilaab's Avatar
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    Re: C1 & C2 - EDEXCEL: 2nd June - ULTIMATE THREAD
    Is there an easy way of solving those trig identities questions in C2?! the book just confused me more
  3. EvenStevens's Avatar
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    Re: C1 & C2 - EDEXCEL: 2nd June - ULTIMATE THREAD
    Just know that cos^2 \theta + sin^2 \theta = 1

    And you can rearrange that for cos^2 \theta = 1 - sin^2 \theta and sin^2 \theta = 1 - cos^2 \theta

    It just takes practise.
  4. Kyalimers's Avatar
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    Re: C1 & C2 - EDEXCEL: 2nd June - ULTIMATE THREAD
    Trig feels piss, especially when you start integrating it in C4 :yep:
  5. Horizontal 8's Avatar
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    Re: C1 & C2 - EDEXCEL: 2nd June - ULTIMATE THREAD
    Sketch the curve with equation  y= (x + 1)^3 - 4(x - 1) showing the coordinates of any points where the curve cross the coordinate axes.

    Also according to the mark scheme it crosses the x-axis at x=1, x=3 and x=-1. I expanded then factorised which works but isn't factorising cubics meant to be C2 (for Edexcel) and this is C1...Is there any other way?

    Any help would be appreciated.
  6. Kyalimers's Avatar
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    Re: C1 & C2 - EDEXCEL: 2nd June - ULTIMATE THREAD
    how many marks is it?
  7. Horizontal 8's Avatar
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    Re: C1 & C2 - EDEXCEL: 2nd June - ULTIMATE THREAD
    3 marks
  8. Kyalimers's Avatar
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    Re: C1 & C2 - EDEXCEL: 2nd June - ULTIMATE THREAD
    well you can get that x=1 and -1 easily by making the brackets = 0

    Then work from there.
  9. EvenStevens's Avatar
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    Re: C1 & C2 - EDEXCEL: 2nd June - ULTIMATE THREAD
    I thought cubic factorisation cropped up in C1 sometimes as well...
  10. 8inchestall's Avatar
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    Re: C1 & C2 - EDEXCEL: 2nd June - ULTIMATE THREAD
    (Original post by sohanshah)
    well you can get that x=1 and -1 easily by making the brackets = 0

    Then work from there.
    I have a problem,and it's to do with the cosine rule
    i know the rule is a^2=b^2 + c^2 - 2bccosA
    So in order to find cosA
    i do
    \frac{a^2-b^2-c^2}{2bc} = cosA

    however this always gives me a minus value and sometimes not the right angle. How come it always gives me the wrong value, have i done something wrong here?
    the question i am stuck on is May 07 question 4(a)

  11. EvenStevens's Avatar
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    Re: C1 & C2 - EDEXCEL: 2nd June - ULTIMATE THREAD
    Ugh, June 05 is such a horrible C1 paper.

    It's not hard... just most of the values are fractions and horrible numbers like that. You waste most of your time multiplying, subtracting and adding fractions together.
  12. Loz17's Avatar
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    Re: C1 & C2 - EDEXCEL: 2nd June - ULTIMATE THREAD
    CosA= b^2 +c^2-a^2/2bc

    And as i recall if you literakky plug those values in and simplify without actually dividing, you'll get 30/45 which is equal to 3/4

    also if the cosine rule is wrong can someone tell me please and sorry for lack of latex, cant use it!

    And a hint for b), think about trig identities!
  13. EvenStevens's Avatar
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    Re: C1 & C2 - EDEXCEL: 2nd June - ULTIMATE THREAD
    To 8inchestall, use the inverted cosine rule...

    cosA = \dfrac{b^2 + c^2 - a^2}{2bc}
  14. 8inchestall's Avatar
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    Re: C1 & C2 - EDEXCEL: 2nd June - ULTIMATE THREAD
    ahh cheers, i get it now. simple mistake of moving all values to the wrong side i guess.
  15. 8inchestall's Avatar
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    Re: C1 & C2 - EDEXCEL: 2nd June - ULTIMATE THREAD
    (Original post by 8inchestall)
    ahh cheers, i get it now. simple mistake of moving all values to the wrong side i guess.
    do sin^2x+cos^2x = 1 and sinx+cosx = 1

    or is the latter wrong?
  16. EvenStevens's Avatar
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    Re: C1 & C2 - EDEXCEL: 2nd June - ULTIMATE THREAD
    No, sinx + cosx = sinx + cosx

    It never = 1.
  17. Kyalimers's Avatar
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    Re: C1 & C2 - EDEXCEL: 2nd June - ULTIMATE THREAD
    (Original post by 8inchestall)
    do sin^2x+cos^2x = 1 and sinx+cosx = 1

    or is the latter wrong?
    the latter is most definitely wrong.
  18. Loz17's Avatar
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    Re: C1 & C2 - EDEXCEL: 2nd June - ULTIMATE THREAD
    Use sin^2x+cos^2=1, put in the value of cos from a) and solve for sin
  19. EvenStevens's Avatar
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    Re: C1 & C2 - EDEXCEL: 2nd June - ULTIMATE THREAD
    If it helps, cosx = \sqrt{1-sin^2x}.

    <_<
    Last edited by EvenStevens; 26-05-2008 at 15:54.
  20. 8inchestall's Avatar
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    Re: C1 & C2 - EDEXCEL: 2nd June - ULTIMATE THREAD
    (Original post by EvenStevens)
    If it helps, cosx = \sqrt{1-sinx^2}.

    <_<
    no need to get cocky, i was just checking to see i had the right stuff written down.
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