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Safety First! Method for calculating Percentage Difference.

Hi all (new here);

like many of you I have a practical tommorow which I'm studying for - but one thing which has stumped me is how to calculate %-differences.

From my limited understanding it should be;

[(Expected Value - Recorded Value)/Expected Value] x 100

Also the significance of the %-difference is that you compared % difference against % error, in which case what conclusions do you draw when one is bigger than the other and vica-versa.

Any help is much appreciated!
Reply 1
Avatar for AlphaWulf
AlphaWulf
I think your equation is correct (in my equally limited knowledge).

For the conclusions thing you have to decide whether your percentage error makes it possible for you to have got the correct answer. So if you got a reading of 100 and you were expecting a reading of 110 you could draw the following conclusions depending on your percentage error:

% error a lot higher than 10 = Quite good evidence for the suspected reading.
% error around 10 = This makes it possible for your result to prove the hypothesis.
% error a lot less than 10 = Suggests that the hypothesis is wrong.

Don't think I've explained it too well, so I can try again if you need. :smile:
Reply 2
Avatar for myxm7
myxm7
OP
No, I think that's pretty well explained thanks. :smile:

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