The Student Room Group
Reply 1
They're the same, because log(x/y) = -log(y/x)
Learn the derivation and you won't get mixed up.

Ka = [H+][A-]/[HA]

therefore [H+] = Ka[HA]/[A-]

take logs throughout

log[H+] = logKa + log([HA]/[A-])

now change signs throughout

pH = pKa - log([HA]/[A-])
Reply 3
Thanks!

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