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Helpppp...please:(
Could someone please look at this paper
http://www.aqa.org.uk/qual/gceasa/qp-ms/AQA-CHM5-W-QP-JUN05.PDF
and then look at 2 (b) (iii) and explain the answer to me. I know what the answer is but it makes no sense to me...
arghhh im depressed...
had enough of revision espesh as its a lovely dayy...
any help will be appreciated thank youu
XX
http://www.aqa.org.uk/qual/gceasa/qp-ms/AQA-CHM5-W-QP-JUN05.PDF
and then look at 2 (b) (iii) and explain the answer to me. I know what the answer is but it makes no sense to me...
arghhh im depressed...
had enough of revision espesh as its a lovely dayy...
any help will be appreciated thank youu
XX
basically at the half neutralisation point, there are equal amounts of A- and HA.
Ka= [H+][A-]/[HA]
The [A-] and [HA] cancel each other out due to having the same volume and same no. of moles, hence same concentration.
This leaves
Ka=[H+]
Taking log of both sides gives -log Ka = -log [H+]
pKa = pH
Ka= [H+][A-]/[HA]
The [A-] and [HA] cancel each other out due to having the same volume and same no. of moles, hence same concentration.
This leaves
Ka=[H+]
Taking log of both sides gives -log Ka = -log [H+]
pKa = pH
spook2575
basically at the half neutralisation point, there are equal amounts of A- and HA.
Ka= [H+][A-]/[HA]
The [A-] and [HA] cancel each other out due to having the same volume and same no. of moles, hence same concentration.
This leaves
Ka=[H+]
Taking log of both sides gives log Ka = log [H+]
pKa = pH
Ka= [H+][A-]/[HA]
The [A-] and [HA] cancel each other out due to having the same volume and same no. of moles, hence same concentration.
This leaves
Ka=[H+]
Taking log of both sides gives log Ka = log [H+]
pKa = pH
Thank youuu....however i don't understand this bit...
This leaves
Ka=[H+]
Taking log of both sides gives log Ka = log [H+]
pKa = pH
Why do you take the logs of both sides and why do you conclude that
pKa = pH
groovyangel2008
Thank youuu....however i don't understand this bit...
This leaves
Ka=[H+]
Taking log of both sides gives log Ka = log [H+]
pKa = pH
Why do you take the logs of both sides and why do you conclude that
pKa = pH
This leaves
Ka=[H+]
Taking log of both sides gives log Ka = log [H+]
pKa = pH
Why do you take the logs of both sides and why do you conclude that
pKa = pH
Because pH = -log [H+] and pKa = -log Ka. Therefore, if Ka = [H+] then we can deduce that pKa = pH.
Not sure if I've made that any more clear, sorry if I haven't. >.<
ahhh i understand thank youu so much for your help wenzel and spook.. i'm tryin 2 revise for my synoptic but as you can tell i've totally forgotten evrthing
Thank you againn
i'm tryin 2 revise for my synoptic but as you can tell i've totally forgotten evrthingThank you againn
evryone is so helpful on TSR i love itt
arrr i hate synoptic...have you got any tips on revisin for it? i need to get an A but i don't know how that's going to happen to be honest
groovyangel2008
arrr i hate synoptic...have you got any tips on revisin for it? i need to get an A but i don't know how that's going to happen to be honest
I'm just doing a bunch of past papers. Plan on looking at the syllabus the day before the exam and revising the areas I feel I don't know too well.
yehh...thanks...i may jus stick to pass papers...have u managed to revise all of unit 5 then?
i really dnt think i'll b gettin an A in this subject
i really dnt think i'll b gettin an A in this subject
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