The Student Room Group

indefinite integrals

Having a problem working out please advise...
need to find the indefinite integral of ..
f(t) = 5cos(10t) + 12e^-3t,
I calculate the answer as ∫(1/2 sin⁡(10)t)+3e^4t+c, but my friend works it out as F(t) becomes simply sin(10t)/2 - 4e^-3t
isnt there meant to be a si in the answer..
many thanks elli
Reply 1
Your friend is correct. The minus sign in e^-3t counts as "-1", so you have to divide by -1 at the front.
Your friend is correct.

aekxdx=akekx+c\displaystyle \int ae^{kx} \, \text{d}x = \frac{a}{k}e^{kx} + c.
Reply 3
Many thanks one and all....
Reply 4
lol i wonder what you've got due in on 2nd July :P OU?!

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