The Student Room Group
Triple D
how do u work 8ncr 1 without a calculator

i thought it was

8!
1!

= 8x7x6x5x4x3x2x1
1

= 40320 which is clearly wrong :confused: :confused:

if you mean 8C1 then this is 8!/1!(8-1)!=8!/7!=8
Reply 2
n (nCr) 1 == n

for any natural number n
Reply 3
It's often easier to use the formula

nCr = n*(n - 1)*(n - 2)*...*(n - r + 1) / r!

instead of

nCr = n!/[r!(n - r)!]

For example,

7C2 = 7*6/2! = 21

is easier to do than

7C2 = 7*6*5*4*3*2*1 / [(1*2)*(1*2*3*4*5)] = 21
Reply 4
Jonny W
It's often easier to use the formula

nCr = n*(n - 1)*(n - 2)*...*(n - r + 1) / r!

instead of

nCr = n!/[r!(n - r)!]

For example,

7C2 = 7*6/2! = 21

is easier to do than

7C2 = 7*6*5*4*3*2*1 / [(1*2)*(1*2*3*4*5)] = 21


Perhaps. Or you could just cancel the 5! from the second expression and it will reduce to 7*6/2!.
Reply 5
JFN
Perhaps. Or you could just cancel the 5! from the second expression and it will reduce to 7*6/2!.

Sure. In my formula the 5! is "pre-cancelled".

Latest