I wonder if anyone could show me the mechanism for the attached reaction. Specifically the alcoholic alkene forming the carbocation using acid. I cant seem to find it or work it out. Dont worry about the other 2 on the image, just the one which is circled and I only need it up until the carbocation is formed as the rest is fine. Thanks in advance - its really appreciated as this has been driving me crazy! Even had the molymod out
The semipinacol is essentially just the pinacol rearrangement with 'no choice'. I've attached an example using tosyl chloride and compared it to the pinacol rearrangement of the corresponding diol. Theres a special case of the semipinacol called the 'Tiffeneau-Demjanov reaction' where beta-amino-alcohols are treated with HNo2/HCl to form the diazonium salt, but I'm not sure you want that
Thanks for the reply but I am already familiar with the pinacol reaction which you have specified above. Its the specific one in the image - I just cant work out how the H+ eliminates the CH2!
Thanks for the reply but I am already familiar with the pinacol reaction which you have specified above. Its the specific one in the image - I just cant work out how the H+ eliminates the CH2!
It doesn't eliminate the CH2 - the alkene picks up the proton so that R4 = CH3 leaving the positive charge on the most stable carbon.