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avogadro's constant question
please help ..my chem teacher is never there and have to do stuff from text books :s
dont understand this !!
calculate the number of itemes in each of the following,
given in Avogadro.C is 6x10^23 ( and i do not understand what this term means ??)
ahhh
okay here is the first question
1) 0.500 mol of CH4 molecules
2) 2.00 moles of h2 molecules
please help ......thanks !!
dont understand this !!
calculate the number of itemes in each of the following,
given in Avogadro.C is 6x10^23 ( and i do not understand what this term means ??)
ahhh
okay here is the first question
1) 0.500 mol of CH4 molecules
2) 2.00 moles of h2 molecules
please help ......thanks !!
amazing-moi
please help ..my chem teacher is never there and have to do stuff from text books :s
dont understand this !!
calculate the number of itemes in each of the following,
given in Avogadro.C is 6x10^23 ( and i do not understand what this term means ??)
ahhh
okay here is the first question
1) 0.500 mol of CH4 molecules
2) 2.00 moles of h2 molecules
please help ......thanks !!
dont understand this !!
calculate the number of itemes in each of the following,
given in Avogadro.C is 6x10^23 ( and i do not understand what this term means ??)
ahhh
okay here is the first question
1) 0.500 mol of CH4 molecules
2) 2.00 moles of h2 molecules
please help ......thanks !!
One mole of any substance has 6*10^23 atoms in it.
Therefore for a) What's half of 6*10^23?
b) what's double it?
Avogadro's constant is 6.02 x 10^23. (Or 6 x 10^23 as you have said)
It is the number of molecules/atoms/ions in 1 mol of a substance.
So a 1 mole of molecules is 6 x 10^23. 1 mole of atoms is also 6 x 10^23.
So for the first question you have 1/2 a mol of CH4 molecules and therefore the total number of molecules is 1/2 of Avogadro's constant, or (6 x 10^23)/2
For the second question you have 2 mols of H2 molecules and so you must multiply Avogadro's constant accordingly.
It is the number of molecules/atoms/ions in 1 mol of a substance.
So a 1 mole of molecules is 6 x 10^23. 1 mole of atoms is also 6 x 10^23.
So for the first question you have 1/2 a mol of CH4 molecules and therefore the total number of molecules is 1/2 of Avogadro's constant, or (6 x 10^23)/2
For the second question you have 2 mols of H2 molecules and so you must multiply Avogadro's constant accordingly.
Avo's constant =
6.02 x 10^23 of , as you said, stuff.
Stuff = atoms, molecules, unit factors, ions, electrons, protons, neutrons (for a laugh you can say there is currently 1.16 x 10^-14 people on this planet). In short, anything
So, a breakdown of this question
For quickness I'll use L for Avo's constant.
1) 0.500 mol of CH4 molecules
CH4 Molecules: (0.5 x L)
Atoms comprising 0.5mol CH4: (0.5 x 5 x L) [5 atoms / molecule]
Carbon Atoms: (0.5 x L)
Hydrogen atoms: (0.5 x 4 x L)
Electrons present: (0.5 x 8 x L) [for each molecule of CH4 there are 8 electrons]
etc
2) 2.00 moles of H2 molecules
Molecules = (2L)
Atoms = (2 x 2L)
Electrons = (2 x 2L) [one electrons for each]
Protons = (2 x 2L) [one H atom is one proton + one electron, normally)]
etc
You get the point
Hope this helps!
Sources:
http://en.wikipedia.org/wiki/Avogadro%27s_constant#Application
6.02 x 10^23 of , as you said, stuff.
Stuff = atoms, molecules, unit factors, ions, electrons, protons, neutrons (for a laugh you can say there is currently 1.16 x 10^-14 people on this planet). In short, anything
So, a breakdown of this question
amazing-moi
1) 0.500 mol of CH4 molecules
2) 2.00 moles of h2 molecules
1) 0.500 mol of CH4 molecules
2) 2.00 moles of h2 molecules
For quickness I'll use L for Avo's constant.
1) 0.500 mol of CH4 molecules
CH4 Molecules: (0.5 x L)
Atoms comprising 0.5mol CH4: (0.5 x 5 x L) [5 atoms / molecule]
Carbon Atoms: (0.5 x L)
Hydrogen atoms: (0.5 x 4 x L)
Electrons present: (0.5 x 8 x L) [for each molecule of CH4 there are 8 electrons]
etc
2) 2.00 moles of H2 molecules
Molecules = (2L)
Atoms = (2 x 2L)
Electrons = (2 x 2L) [one electrons for each]
Protons = (2 x 2L) [one H atom is one proton + one electron, normally)]
etc
You get the point
Hope this helps!
Sources:
http://en.wikipedia.org/wiki/Avogadro%27s_constant#Application
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