Chemistry equation

It's a work in progress. Feel free to edit and post.

Reply 61

How's this?? Mind checking it this time :biggrin:

Find the Compound Formula for AB where

A^{x+} , B^{y-}

Step 1.

A^{x+} + B^{y-}

Step 2. If

x = y

, they combine like this:

AB

Step 3. If not...:

\frac{x}{y}

cancel down this fraction into it's simplest form, like how

\frac{2}{4} = \frac{1}{2}

Step 4. Call this 'cancelled down' version of x and y as

\frac{m}{n}

Step 5. The Compound can be written as

A_n(B)_m

Example:

1.

Al^{3+} , S_2O_3^{2-}

2. 3 is not equal to 2

3.

\frac{3}{2}

\frac{3}{2} = \frac{m}{n}

\therefore

Formula =

Al_2(S_2O_3)_3

Reply 62

Oxy

Malsi101

oh K..I get it.

so how about 2,2 dibromo-3-fluorobutane

:p:

2 bromine atoms bonded to the 2nd carbon in the chain, with a flourine bonded to the 3rd. The rest are filled with Hydrogens.

Reply 63

Malsi101

oh K..I get it.

so how about 2,2 dibromo-3-fluorobutane

:p:

4 carbons, 2 bromines, 1 fluorine. Both bromines are attached to the second carbon from one end, and the flourine to the third (counting from the same end of the chain.

So first carbon would have 3Hs, second carbon would have 2 Bromines, third carbon 1 F and 1 H, and the last 3Hs again

Reply 64

magnesium hydroxide:

Mg2+ + OH- + Mg2+ + 2OH_ = Mg(OH)2

Silver Carbonate:

Ag+ + CO2-3 = 2Ag+ + CO2-3 =

Ag_2 CO_3

copper sulphate:

Cu2+ + SO2-4 =

CuSO_4

Reply 65

sohanshah

How's this?? Mind checking it this time :biggrin:

Find the Compound Formula for AB where

A^{x+} , B^{y-}

Step 1. Find

x - y

Step 2. If the above does not equal 0, then work out, how many x's and/or how many y's will be required to make

k_1 x - k_2 y = 0

Step 3. Put

k_1

after A and

k_2

after B thus:

A^{x+}_{k_1} , (B^{y-})_{k_2}

Step 4. Put the ions together:

A^{x+}_{k_1} , (B^{y-})_{k_2} \rightarrow A_{k_1} (B)_{k_2}

where

k_1

and

k_2

are integers.

Example:

Al^{3+} , S_2O_3^{2-}

1. 3 - 2 = 1

2. (2)3 - (3)2 = 0 therefore

k_1 = 2 , k_2 = 3

Al^{3+}_2 , (S_2O_3^{2-})_3

Al^{3+}_2 , (S_2O_3^{2-})_3 \rightarrow Al_2(S_2O_3)_3

Not to be pedantic, but surely it's x- Mod(y) :p:

Ignore what I just said btw hehe

Reply 66

Malsi101

magnesium hydroxide:

Mg2+ + OH- + Mg2+ + 2OH_ = Mg(OH)2

Silver Carbonate:

Ag+ + CO2-3 = 2Ag+ + CO2-3 =

Ag_2 CO_3

copper sulphate:

Cu2+ + SO2-4 =

CuSO_4

Perfect on all three counts. You deserve a nice break now (unless you're too pumped up from all the chemistry :p:

)

Reply 67

I'm sure there was one exception to this rule which is why I didn't write down: Exchange the x and y and have it onthe bottom instead of the top.

Reply 68

woo tis what I got too.

I just knew the 2, 2 one which makes it di just didn't get how the 1 , 2 would make it di considering they're not on the same Carbon.

so for example I was getting mixed up with the fact that 1, 2 meant br on 1 and 2, but in class we did 1-bromo-2di bromo which meant 1 bromo on the first one and 2 on the second thus making it dibromo.

if you get what Im saying..the 1 , 2 should be 1 bromo 2 di bromo making 1 br on the first carbon and 2 on the second..but that is probably way off I know but is anything I said in this post correct :biggrin:

Reply 69

On a slightly different topic, does 2-methylbutan-1-ol have an enantiomer?

Reply 70

Sanjetti

Perfect on all three counts. You deserve a nice break now (unless you're too pumped up from all the chemistry :p:

)

yaya go me :woo:

thanks..I love chemistry..just a shame I haven't learnt much..but I have today :woo:

Reply 71

Me too actually. Mayb I was wrong. Will change my post.

Thanks

Reply 72

Find the Compound Formula for AB where

A^{x+} , B^{y-}

Step 1.

A^{x+} + B^{y-}

Step 2. If

x = y

, they combine like this:

AB

Step 3. If not...:

\frac{x}{y}

cancel down this fraction into it's simplest form, like how

\frac{2}{4} = \frac{1}{2}

Step 4. Call this 'cancelled down' version of x and y as

\frac{m}{n}

Step 5. The Compound can be written as

A_n(B)_m

Example:

1.

Al^{3+} , S_2O_3^{2-}

2. 3 is not equal to 2

3.

\frac{3}{2}

\frac{3}{2} = \frac{m}{n}

\therefore

Formula =

Al_2(S_2O_3)_3

Credit to GHOSH-5 for revision of post.

Reply 73

Is anyone here that has a chem degree wanting to teach chemistry as a career? :smile:

Reply 74

EierVonSatan

possibly...

oo cool

Reply 75

EierVonSatan

yup

Is the chiral centre the carbon thats attached to the CH2OH and the CH(CH3) groups?

(sorry of chirality has no association with enantiomers)

Reply 76

Malsi101

yaya go me :woo:

thanks..I love chemistry..just a shame I haven't learnt much..but I have today :woo:

Np, yeh chemistry is great hehe. And I'm sure you'll learn a lot, and ace the AS at the end of the year. Good luck!

Reply 77

Sanjetti

Np, yeh chemistry is great hehe. And I'm sure you'll learn a lot, and ace the AS at the end of the year. Good luck!

why thank you*praysandhope*

:biggrin:

you too btw :biggrin:

Reply 78

EierVonSatan

chirality is very much associated with enantiomers - carbon 2 has the chiral center - four different groups are H, CH3, C2H5 and CH2OH

Yeh that's right- Thanks

Reply 79