The Student Room Group
Polymorphing
How do I calculate the pH of the aqueous solution:
4.50 x 10^-4 mol dm^-3 H2SO4


The answer is not quite as straightforward as it seems, but it does depend on the level you are studying.

It's quite likely that you are expected to treat sulphuric acid as a dibasic acid and assume that the molarity of the hydrogen ions is 2 x 4.50 x 10-4 mol dm-3 = 9 x 10-4 and then use pH = -log10[H+]

In reality the second hydorgen ion is not dissociated 100% and the true [H+] lies somewhere between 4.50 x 10-4 and 9 x 10-4, however you can only work out where if you know the ka value for the second dissociation:

HSO4- <==> SO42- + H+

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