Why do you start at one end to get 3-bromo and then start at the other end to get two. How is it you are going from right to left then left to right; I thought you have to keep it constant in the chain, and keep going from right to left, and not then change.
Why do you start at one end to get 3-bromo and then start at the other end to get two. How is it you are going from right to left then left to right; I thought you have to keep it constant in the chain, and keep going from right to left, and not then change.
sorry about that ramble.
No we didn't start at one end and then the other. Maybe you should draw the structure out in a piece of paper...
Why do you start at one end to get 3-bromo and then start at the other end to get two. How is it you are going from right to left then left to right; I thought you have to keep it constant in the chain, and keep going from right to left, and not then change.
sorry about that ramble.
You prioritise alphabet in this case, then you try to keep the numbers lowest (ie. 3 and 2, not 3 and 4). This would mean stating the bromo first, as it's 'b' in the alphabet, and but keeping it in numerical order isn't possible after doing this, as you've already used alphabet. When there's 2 methyls, for example, it would just be 2,3- dimethylpentane.
The thing I want to ask: is it okay to go from 3 to 2: are you allowed to go backwards in numbers?
Because I would have kept constant from right to left and said 3-bromo-4methylpentane.
My teacher never tells me these rules
Whichever way around it is, go alphabetically and use the smallest numbers possible.
Like 3,4-dimethylpentane is impossible; it should be 2,3-dimethylpentane. Also, instead of 2-methyl-4-bromopentane it would be 2-bromo-4-methylpentane because they're in the same relative positions but the bromo- prefix is first alphabetically. xx
I think that would be 2,2,4-trimethylpentane. So there are more of the lower number.
Yes, sir! You are correct. Remember the 'trimethyl' becuase there are 3 seperate CH3 groups. Never really encountered anything with 4, but i think it'd probably be tetramethyl. (2 is di-, obviously)
It's 2,4,4-dimethylpentane. If there are three methyl groups attached to a carbon, a “tri" prefix should be added. If there are four, it should be "tetra", etc.
Is it not the case that the groups don't have to be attached to the same carbon? I swear you can say 1,2-dibromopropane. I'm sure I was taught that it was the total number of groups, not just the number on one carbon.
Either 3-bromo, 4-methylhexane or 4-bromo, 3-methylhexane. They are the same compound. There may be standard ways of nomencrature in this instance, however at A-level both are acceptable.
Either 3-bromo, 4-methylhexane or 4-bromo, 3-methylhexane. They are the same compound. There may be standard ways of nomencrature in this instance, however at A-level both are acceptable.