Intergration question

how do you intergrate

x(4-x^2)^0.5

tried using substitution and by parts and they dont work........

plz help!!!!!

thanks

Substitution should work; what's the derivative of 4 - x^2 ?

Substitution does work.

edit: Damn you, GA :p:

x is -1/2du
so its a substitution intergration

Glutamic Acid

Substitution should work; what's the derivative of 4 - x^2 ?

What did you use to sub? 4-x^2 or (4-x^2)^0.5 ?

derivative of 4-x^2 is -2x

u=4-x^2, du=-2x

Grimmjow

What did you use to sub? 4-x^2 or (4-x^2)^0.5 ?

derivative of 4-x^2 is -2x

And -2x differs from x by a constant multiplier, (-1/2), so u = 4 - x^2 will work.

thanks ppl got it :smile:

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