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Trigonmetry
See attachment for the diagram of the triangles. The 2 triangles are similar, and the first part of the question is to write down the length of the side marked x....this is 10.5cm
The next part of the question says, given that tanx= 3, what are the values of sinx and cos x respectively.
The next part of the question says, given that tanx= 3, what are the values of sinx and cos x respectively.
Start with using tanx=sinx/cosx.
Nandoz
See attachment for the diagram of the triangles. The 2 triangles are similar, and the first part of the question is to write down the length of the side marked x....this is 10.5cm
The next part of the question says, given that tanx= 3, what are the values of sinx and cos x respectively.
The next part of the question says, given that tanx= 3, what are the values of sinx and cos x respectively.
I think you mean 11.5.
Are the triangles right angled?
EDIT: 10.5
. That's why.tan of an angle is defined to be the ratio between the opposite and adjacent.
If you had an angle, y, you could name sides relative to that angle.
Hyp for the longest, adj for the nearest and opp for the side furthest away.
As all triangle with a an angle y are similar, (right triangles), it follows that the ratio of the sides are always the same.
Therfore, tan is defined to be o/a, which means you draw a right triangle, and from your angle you put 3 for opposite and 1 for adjacent's length. You then work out the length of the hypotenuse using pythagoras.
Remember the definitions:
sin(x) = o/h cos(x) = a/h.
If you had an angle, y, you could name sides relative to that angle.
Hyp for the longest, adj for the nearest and opp for the side furthest away.
As all triangle with a an angle y are similar, (right triangles), it follows that the ratio of the sides are always the same.
Therfore, tan is defined to be o/a, which means you draw a right triangle, and from your angle you put 3 for opposite and 1 for adjacent's length. You then work out the length of the hypotenuse using pythagoras.
Remember the definitions:
sin(x) = o/h cos(x) = a/h.
Nandoz
so does sin x = 3/3.16 and cos x = 1/3.16
You can make them into slightly nicer fractions.
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