The Student Room Group
Reply 1
Heat.
Reply 2
Surely it does this by releasing a photon though. The only energy the two moleucles can give up is their kinetic energy. This can be used to promote electrons to different energy levels, etc. However, the intermediate product must now have 'give up' some energy. It can't just suddenly go faster (i.e. raise the temperaute) unless there is something to increase it's velocity - the only it could do this is to undergo conservation of momentum by ejecting a photon. However, this is of course not practical (or feasible), as the photon would have to have energy in the GeV's. However, does the intermediate product first releaase a photon (in which case electrons would have to decrease in nergy level (but where?)), adn then this photon is absorbed by the surroundings (and how exactly does infa-red etc increase the temperature? The photon could be absorbed and remitted, and there would be slight recoil, but I don't see how that would be enough).

I'm not quite sure as to actually how the intermediate product releases it's excess energy.
Reply 3
DeanK2
Surely it does this by releasing a photon though. The only energy the two moleucles can give up is their kinetic energy. This can be used to promote electrons to different energy levels, etc. However, the intermediate product must now have 'give up' some energy. It can't just suddenly go faster (i.e. raise the temperaute) unless there is something to increase it's velocity - the only it could do this is to undergo conservation of momentum by ejecting a photon. However, this is of course not practical (or feasible), as the photon would have to have energy in the GeV's. However, does the intermediate product first releaase a photon (in which case electrons would have to decrease in nergy level (but where?)), adn then this photon is absorbed by the surroundings (and how exactly does infa-red etc increase the temperature? The photon could be absorbed and remitted, and there would be slight recoil, but I don't see how that would be enough).

I'm not quite sure as to actually how the intermediate product releases it's excess energy.


No, their extra potential energy is converted into kinetic energy.
Reply 4
TableChair
No, their extra potential energy is converted into kinetic energy.


Firstly: what 'extra' potential energy are you talking about? (They are subject to no forces that can give them potential energy, nor where they ever subject to any, so the integral of -Fdx is most obviously zero.

Even if the molecule did have energy, I am not disputing that it would need to be converted to kinetic energy in order to raise the temperature. however, the molecule does not think 'now would be a good time to increase my energy'. Instead, it must somehow release a particle (such as a phton), and take use of the conservation of momentum to achieve extra kinetic energy.

Both of your above posts seem to give me the impression that you are merely stating what happens, without a mechanism - I clearly wan tot know HOW this happens.

Thanks for the replies though.
Reply 5
An intermediate species will have a higher potential energy than the reactants. Of course it can have potential energy. Consider a system of point charges, the total potential energy of the system depends on the positions of the charges.
Reply 6
TableChair
An intermediate species will have a higher potential energy than the reactants. Of course it can have potential energy. Consider a system of point charges, the total potential energy of the system depends on the positions of the charges.


They can't. Think about it.

EDIT: I mean the intermediate cannot, obviously your example is correct but not analogous
Reply 7
DeanK2
They can't. Think about it.

EDIT: I mean the intermediate cannot, obviously your example is correct but not analogous


The intermediate is simply a different arrangement, so yes, it can.

http://en.wikipedia.org/wiki/Reactive_intermediate

A quote from there: "Their potential energy with respect to reactants or previous intermediates is defined to have a minimum of depth greater than available thermal energy arising from temperature, with an exact value RT, where R is gas constant and T is temperature."

So they do have a different potential energy. Have you ever seen a graph of Energy (Potential enrgy) against reaction coordinate.

How is my example not analogous :s-smilie:

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