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Question about a oxalic acid solution.

I need some help with this question. Could someone work it out so I understand it. Thanks

It takes 37.32 mL of a 0.103 N KMnO4 solution to neutalize 23.53 mL of an unknown oxalic acid solution. What is the normality of the oxalic acid solution?
The equation you need to use is;

2MnO4- + 6H+ + 5H2C2O4 --> 2Mn2+ + 10CO2 + 8H2O

by normality do you mean concentration? If so, calculate how many moles of the permanganate ion there are then use the above ration to find out how many moles of oxalic acid you had at the start, then work out the concentration :smile:

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