Results are out! Find what you need...fast. Get quick advice or join the chat
x

Unlock these great extras with your FREE membership

  • One-on-one advice about results day and Clearing
  • Free access to our personal statement wizard
  • Customise TSR to suit how you want to use it

C3 exponential differentiation

Announcements Posted on
Find your uni forum to get talking to other applicants, existing students and your future course-mates 27-07-2015
  1. Offline

    ReputationRep:
    I would appreciate some help with this question thanks!

    Given that T is a measure of temperature in degrees C, t is the time in minutes and that T = 20 + 60e^-0.1t, t > or equal to 0

    a) Find dT/dt
    I worked it out and I got -6e^-0.1t

    b) Find the value of T at which the temperature is decreasing at a rate of 1.8 degrees C per minute

    I thought I would do -6e^-0.1t = 1.8
    but then I am stuck, the answer I should get is 38 :confused:
  2. Offline

    ReputationRep:
    i thaught it would be -60 not -6
  3. Offline

    ReputationRep:
    (Original post by Hrov)
    i thaught it would be -60 not -6
    I did it wrong with latex, I needed to differentiate 60e to the power of -0.1t
    which is -6e to the power of -0.1t (same as the answer in the book)
  4. Offline

    ReputationRep:
    (Original post by kinglrb)
    I would appreciate some help with this question thanks!

    Given that T is a measure of temperature in degrees C, t is the time in minutes and that T = 20 + 60e^-0.1t, t > or equal to 0

    a) Find dT/dt
    I worked it out and I got -6e^-0.1t

    b) Find the value of T at which the temperature is decreasing at a rate of 1.8 degrees C per minute

    I thought I would do -6e^-0.1t = 1.8
    but then I am stuck, the answer I should get is 38 :confused:
    ln ?
  5. Offline

    ReputationRep:
    I answered this EXACT question a few hours ago.
    I'll copy out my solution for you


    your first answer is correct.

    Then, find out the value for "t" and set the expression you found in a) equal to -1.8. (It's a decrease remember, so negative)

    so basically -6e^0.1t = -1.8, take logs of both sides and solve for t.

    Using your value of t (I get ~12.04 ish) substitute this into the original expression for T (not dT/dt).

    So T = 60e^(-0.1 x 12.04) + 20

    should give 38 *C

  6. Offline

    ReputationRep:
    (Original post by me, myself and I)
    I answered this EXACT question a few hours ago.
    I'll copy out my solution for you


    your first answer is correct.

    Then, find out the value for "t" and set the expression you found in a) equal to -1.8. (It's a decrease remember, so negative)

    so basically -6e^0.1t = -1.8, take logs of both sides and solve for t.

    Using your value of t (I get ~12.04 ish) substitute this into the original expression for T (not dT/dt).

    So T = 60e^(-0.1 x 12.04) + 20

    should give 38 *C

    thats it ^^
  7. Offline

    ReputationRep:
    (Original post by me, myself and I)
    I answered this EXACT question a few hours ago.
    I'll copy out my solution for you


    your first answer is correct.

    Then, find out the value for "t" and set the expression you found in a) equal to -1.8. (It's a decrease remember, so negative)

    so basically -6e^0.1t = -1.8, take logs of both sides and solve for t.

    Using your value of t (I get ~12.04 ish) substitute this into the original expression for T (not dT/dt).

    So T = 60e^(-0.1 x 12.04) + 20

    should give 38 *C

    Ahhh brillaint, thanks! I was getting 12.04 but forgot to add it back in so I was doing again and again. Thank you!
  8. Offline

    ReputationRep:
    (Original post by kinglrb)
    Ahhh brillaint, thanks! I was getting 12.04 but forgot to add it back in so I was doing again and again. Thank you!
    glad I could help! Just thought it was such a coincidence when I saw the question lol, I have an interview tomorrow so I've been preparing for it and getting stressed out, haha

  9. Offline

    ReputationRep:
    (Original post by me, myself and I)
    glad I could help! Just thought it was such a coincidence when I saw the question lol, I have an interview tomorrow so I've been preparing for it and getting stressed out, haha

    oooh, interview for what if you don't mind me asking?
  10. Offline

    ReputationRep:
    (Original post by kinglrb)
    oooh, interview for what if you don't mind me asking?
    it was for civil engineering at imperial
    fingers crossed it went well, the interview wasn't as daunting as I thought it would be and the interviewer was lovely! but I don't want to think about it too much in case I don't get an offer on ucas! Loved the place though!
  11. Offline

    ReputationRep:
    (Original post by me, myself and I)
    it was for civil engineering at imperial
    fingers crossed it went well, the interview wasn't as daunting as I thought it would be and the interviewer was lovely! but I don't want to think about it too much in case I don't get an offer on ucas! Loved the place though!
    Oh brillaint! I am sure you did great, Good luck with that
  12. Offline

    ReputationRep:
    (Original post by kinglrb)
    Oh brillaint! I am sure you did great, Good luck with that
    Thanks!
    are you applying this year?
  13. Offline

    ReputationRep:
    (Original post by me, myself and I)
    Thanks!
    are you applying this year?
    Yupp :yep: , I've applied for medicine at Newcastle, Leicester, Aberdeen, Glasgow and Chemical Engineering at UCL. I still haven't got any interviews so am still waiting :woo:
  14. Offline

    ReputationRep:
    (Original post by kinglrb)
    Yupp :yep: , I've applied for medicine at Newcastle, Leicester, Aberdeen, Glasgow and Chemical Engineering at UCL. I still haven't got any interviews so am still waiting :woo:
    Ooooh of course, just realised it says so in your sig! lol, good luck with them all though
  15. Offline

    ReputationRep:
    (Original post by me, myself and I)
    Ooooh of course, just realised it says so in your sig! lol, good luck with them all though
    Thank you!

Reply

Submit reply

Register

Thanks for posting! You just need to create an account in order to submit the post
  1. this can't be left blank
    that username has been taken, please choose another Forgotten your password?
  2. this can't be left blank
    this email is already registered. Forgotten your password?
  3. this can't be left blank

    6 characters or longer with both numbers and letters is safer

  4. this can't be left empty
    your full birthday is required
  1. By joining you agree to our Ts and Cs, privacy policy and site rules

  2. Slide to join now Processing…

Updated: November 19, 2008
TSR Support Team

We have a brilliant team of more than 60 Support Team members looking after discussions on The Student Room, helping to make it a fun, safe and useful place to hang out.

Poll
Would you consider Clearing if you missed your offer?
Results and Clearing

Results are coming...

No sweat. Here's all you need to make sure you're ready

new on tsr

What's your life ambition?

Graduating, travelling, owning a business?

Study resources
x

Think you'll be in clearing or adjustment?

Hear direct from unis that want to talk to you

Get email alerts for university course places that match your subjects and grades. Just let us know what you're studying.

Quick reply
Reputation gems: You get these gems as you gain rep from other members for making good contributions and giving helpful advice.