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Beer-Lambert Law Help.

Hi there,
I'm currently confused on this beer lambert law question. Basically, I'm told that ϵ\epsilon of a substance dissolved in hexane is 855 mol−1cm−1mol^-1 cm^-1 at 270nm.
a) It asks me to calculate the concentration to give an absorbance of 2.0 if light of this wavelength is passed through a 1cm cell.

My solution is A=ϵ×c×lA = \epsilon \times c \times l
c=2.0855×1c = \frac{2.0}{855 \times 1}
=2.34×10−3moldm−3= 2.34 \times 10^{-3} mol dm^{-3}. Correct?

b) The second part asks to calculate the corresponding percentage reduction in light internsity that would result.

Here is where I'm kinda stuck. From my understanding, do you bascially use A=log10I0IA = log_{10} \frac{I_0}{I}? Sub in 100 for I0I_0 and 2 for AA to obtain 102.0=100I10^{2.0} = \frac{100}{I} where I is to be found?

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