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Old 29-12-2008: 29th December 2008 13:58 #1 
shriya shriya is offline Female
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Default edexcel core 2
 
does anyone have any revision notes?? mostly on differentiation and integration and binomial expansion
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Old 29-12-2008: 29th December 2008 14:05 #2 
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Default Re: edexcel core 2
 
Differentiation:

y = kx^n
\implies dy/dx = nkx^{n-1}

Turning points occur at dy/dx = 0. A function is increasing when f'(x)>0 and decreasing when f'(x) < 0. At a turning point, if f''(x) > 0, it's a minimum or if < 0, it's a maximum.

Integration:

dy/dx = kx^{n}
\implies y = \frac{k}{n+1}x^{n+1} + c

To find the area under the curve: integrate to find an expression in terms of x and then plug in the two values of x in which the area lies between (note that you get a negative answer if the curve goes below the x-axis at any point, so take care of that) and subtract them.

That pretty much covers 98% of differentiation and integration (C2 style). The best way to revise, though, is to do as many questions as you can get your hands on (particularly solomon papers).
 

Last edited by Swayum : 29-12-2008 at 14:07.

Old 29-12-2008: 29th December 2008 14:43 #3 
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Default Re: edexcel core 2
 
Originally Posted by Swayum
Differentiation:

y = kx^n
\implies dy/dx = nkx^{n-1}

Turning points occur at dy/dx = 0. A function is increasing when f'(x)>0 and decreasing when f'(x) < 0. At a turning point, if f''(x) > 0, it's a minimum or if < 0, it's a maximum.

Integration:

dy/dx = kx^{n}
\implies y = \frac{k}{n+1}x^{n+1} + c

To find the area under the curve: integrate to find an expression in terms of x and then plug in the two values of x in which the area lies between (note that you get a negative answer if the curve goes below the x-axis at any point, so take care of that) and subtract them.

That pretty much covers 98% of differentiation and integration (C2 style). The best way to revise, though, is to do as many questions as you can get your hands on (particularly solomon papers).

thank you
 
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