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Empircal formula ?

I was asked to work out the following:

Compound X contains only boron and hydrogen. The percentage by mass of boron X is 81.2%. In the mass spectrum of X the peak at the largest value m/z occurs at 54.

Calculate the empircal formula.

I worked it out like this:

81.2/10.8=7.5 18.8/1=18.8 However the answer says: B2:h:5 ?!?!
7.5/7.5=1 18.8/7.5=2.5

1: 2


It then says deduce the molecular mass - answer says its: B4: H10!?

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18.8/7.5 = 2.5 so the ratio is 1: 2.5 which can't exist so it must be 2:5, if it was 2.1 you could round down but its too far out for errors
Reply 2
The start of what you've done is right

81.2/10.8 = 7.5 18.8/1 = 18.8

That's a 7.5:18.8 ratio

Divide by the smallest number

7.5/7.5 = 1
18.8/7.5 = 2.5

That's a 1:2.5 ratio

The empirical formula is the simplest whole number ratio, 2.5 is not a whole number

Get it to a whole number by multiplying by 2

That's a 2:5 ratio

Therefore, B2H5
Reply 3
Sure it didn't ask deduce the molecular formula?
Reply 4
Ohhh, so if it was 2.6 would the ratio be 2:6?
Reply 5
Malsi101
Sure it didn't ask deduce the molecular formula?


Yes lol, appologies!
Reply 6
Baby Princess
Yes lol, appologies!



:smile:
Reply 7
Baby Princess
Ohhh, so if it was 2.6 would the ratio be 2:6?



no lol..they wouldn't normally give you 2.6 the reason why 2.5 is 5 is because you have to double it because it's not a whole number.

so

1:2.5
would be
2:5

because you've doubled 1 to get 2 and 2.5 to get 5.
Reply 8
Ahhh okay thanks lol, it makes sense!! It confused me ALOT and was thinking godamnit my revisions just going to waste !!!!
Reply 9
The most complicated I've seen is like, 2:3.33 and you have to times it by three. I don't think they'll give you something like 2.7, you'd just have to assume that that's wrong.
Reply 10
You missed a step
First use an accurate calculator i recommend you to buy the Casio fx-991 Ex or a higher version

1:you subtracts 100-(81.2)= 18.2% Hydrogen

2:number of moles of B= 81.2 g / 11=7.38 mol B
number of moles of H= 18.2 g / 1 =18.2 mol H

3 : Divide by the Fewest number of moles.<That would be the Boron Moles
B=7.38/7.38=1
H=18.2/7.38=2.4

4: Now here is a trick some student dont know H=2.4 >> the fraction is 0.4 to solve this or any other Empirical formula problem follow these steps

a. 1/4(the fraction) =0.25

5: Gongrat you solved your ordeal :P

take the 0.25 and divide the

c.B = 1 / 0.25 = 4

d.H = 2.4 / 0.25 = 9.6 which equal 10

SO MF is B4H10



SOLVED
Reply 11
Lol its not that complicated ive seen worse. I study the Chang College book believe me that book is a nightmare but i carry it a lot it is My reference.
Reply 12
Woody.
The start of what you've done is right

81.2/10.8 = 7.5 18.8/1 = 18.8

That's a 7.5:18.8 ratio

Divide by the smallest number

7.5/7.5 = 1
18.8/7.5 = 2.5

That's a 1:2.5 ratio

The empirical formula is the simplest whole number ratio, 2.5 is not a whole number

Get it to a whole number by multiplying by 2

That's a 2:5 ratio

Therefore, B2H5


:shifty:

Excuse me But it is not the right way.Ive Already explained how you can solve it.

Extra Empirical formula problem:
Ascorbic acid(vitamin C) Cures scurvy.it is composed of 40.92% carbon,4.58% Hydrogen,54.50% Oxygen.Determine its Empirical Formula.



GOOD LUCK:biggrin:
Reply 13
AVAINTEX
:shifty:

Excuse me But it is not the right way.Ive Already explained how you can solve it.

Extra Empirical formula problem:
Ascorbic acid(vitamin C) Cures scurvy.it is composed of 40.92% carbon,4.58% Hydrogen,54.50% Oxygen.Determine its Empirical Formula.



GOOD LUCK:biggrin:


Uhh, firstly I explained how to do it before you. It clearly is the right way as myself, EierVonSatan, and the mark scheme have the same answer. It's the way I've been taught by qualified Chemistry teachers and I am inclined to believe that way rather than yours as I don't really know you nor your method.
Reply 14
i think AVAINTEX is on crack.I mean the OP worked to the answer ages ago. Now move on please:smile:
Well this is certainly...different :p: There's nothing wrong with Woody's method :nah:

AVAINTEX, I'm completely lost with your method from step 4 onwards :confused:

Also, the empirical formula contains the lowest ratio of whole number elements, so in this case its B2H5.
Reply 16
EierVonSatan
Well this is certainly...different :p: There's nothing wrong with Woody's method :nah:

AVAINTEX, I'm completely lost with your method from step 4 onwards :confused:

Also, the empirical formula contains the lowest ratio of whole number elements, so in this case its B2H5.


Yes This is the accurate way to solve any Empirical or molecular Formula problem in chemistry.
AVAINTEX
Yes This is the accurate way to solve any Empirical or molecular Formula problem in chemistry.


cool, thanks! :woo:
Reply 18
:laughing:
Reply 19
lol I Explained the Molecular formula.. Dummy me T_T

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