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Time-Bandwidth product
The question is find an expression relating the bandwidth delta v of a pulse to its centre frequency lambda0.
The answer just says that using c = v * lambda, we get delta v = (c*delta lambda)/ (lambda0^2)
I'm not entirely sure how that works though so an explanation would be much appreciated. Thanks
The answer just says that using c = v * lambda, we get delta v = (c*delta lambda)/ (lambda0^2)
I'm not entirely sure how that works though so an explanation would be much appreciated. Thanks
basically you differentiate the expression .
freq = c / lambda wrt to lambda
freq = c / lambda wrt to lambda
What level do you want an answer at?
You can make lambda -> lambda + delta lambda
Expand using series expansion
rearrange
Its just the same as differentiaiting. Calculus is how we find rates of change of one quantity with respect to another quantity. Here you are interested in how freq changes when lambda changes .
Lambda0 is just lambda
You can make lambda -> lambda + delta lambda
Expand using series expansion
rearrange
Its just the same as differentiaiting. Calculus is how we find rates of change of one quantity with respect to another quantity. Here you are interested in how freq changes when lambda changes .
Lambda0 is just lambda
. Thanks for the helpRelated discussions
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