The Student Room Group

Making up a solution

Im really stuck on this question:

How would you prepare a 0.05moldm^-3 soln of HCL(aq) given a 1000cm^3 graduate flask and a 1.00moldm^-3 soln of the acid.

is it that you are trying to half the concentration? would that mean diluting it? and what is the significance of the size of the graduated flask as other parts of the question have different sized graduated flasks.

thanks
You need to dilute it. In that 1000cm^3 flask, you need 0.05 moles of HCl. In your stock solution you have 1 mole. Can you work out the dilution factor?

Once you've worked that out, the procedure will be: Fill the flask to approximately 800mL of water, add the aliquot of acid, then top it up with water upto the mark.
You need to dilute it. In that 1000cm^3 flask, you need 0.05 moles of HCl. In your stock solution you have 1 mole. Can you work out the dilution factor?

Once you've worked that out, the procedure will be: Fill the flask to approximately 800mL of water, add the aliquot of acid, then top it up with water upto the mark.
Reply 3
So is the diluation factor 20? Because the concentration is going from 1.00 moles to 0.005 moles so thats a twentieth of the initial concentration?
That's correct :smile:

So you need 50mL of your 1 molar stock solution.

Latest