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Help!

Hi, I have to do an exam paper for homework, its Chemistry if Natural Resources, June 07. I'm stuck on question 2 b ii, the question is:

16.20cm3 of 0.0100 mol dm-3 aqeous iodine solution was needed to react with 50.00cm3 of wine. Calculate the number of moles iodine used in the titration.

I have no idea how to even start!! Thank you.
Reply 1
u can ignore the part of the wine, all you gotta do is transfer 16.20cm3 of 0.0100 mol dm-3 of iodine into moles
so first:

16.20 / 100 (as its 0.01 molar, to bring it to 1.0)
then divide that by RAM of iodine and u got the moles
Thanks!
Reply 3
:confused: Isn't it just:

Moles = concentration * vol (cm^3)/1000
= 0.01 * 16.2/1000
= 1.62 x 10^-4

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